我需要重置或杀死(使用上下文。完成)当前的 IDialogContext 实例并创建一个新实例并在不同的函数中使用它。我怎样才能创建这样的实例，IDialogContext是一个接口。可能吗？
这是我尝试从中调用函数"selfredirect"的函数
private async Task ApprovalConfirm(IDialogContext context, IAwaitable<IMessageActivity> result)
{
var message = await result;
xxxticket xxxticketobject = new xxxticket();
if (message.Text.Contains("yes"))
{
xxxticketobject = context.ConversationData.Get<xxxticket>("xxxcard");
if (xxxticketobject.action == "Approve")
await context.PostAsync("Accepted");
else
await context.PostAsync("Rejected");
context.ConversationData.RemoveValue("xxxfinalcard");
context.Reset();// *This is what I want to do...clear context and then call the following function*
await SelfRedirect(context, context.UserData.Get<string>("CurrentQuery"), "Approval");
}
else if (message.Text == "no")
{
await context.PostAsync("Thank you");
context.Done(context);
}
else
await SelfRedirect(context, context.UserData.Get<string>("CurrentQuery"), null);
}
自重定向功能
public static async Task SelfRedirect(IDialogContext context, string msg, string intent=null)
{
try
{
DialogLuis LUISDialog = new DialogLuis();
IMessageActivity message = context.MakeMessage();
message.Text = msg;
var tasks = LUISDialog.services.Select(s => s.QueryAsync(message.Text, context.CancellationToken)).ToArray();
var results = await Task.WhenAll(tasks);
var winners = from result in results.Select((value, index) => new { value, index })
let resultWinner = LUISDialog.BestIntentFrom(result.value)
where resultWinner != null
select new LuisServiceResult(result.value, resultWinner, LUISDialog.services[result.index]);
if (intent != null)
{
winners = from result in results.Select((value, index) => new { value, index })
let resultWinner = new IntentRecommendation(intent)
where resultWinner != null
select new LuisServiceResult(result.value, resultWinner, LUISDialog.services[result.index]);
}
var winner = LUISDialog.BestResultFrom(winners);
if (winner == null)
{
throw new InvalidOperationException("No winning intent selected from Luis results.");
}
if (winner.Result.Dialog?.Status == DialogResponse.DialogStatus.Question)
{
var childDialog = await LUISDialog.MakeLuisActionDialog(winner.LuisService,
winner.Result.Dialog.ContextId,
winner.Result.Dialog.Prompt);
context.Call(childDialog, LUISDialog.LuisActionDialogFinished);
}
else
{
IAwaitable<IMessageActivity> item = null;
await LUISDialog.DispatchToIntentHandler(context, item, winner.BestIntent, winner.Result);
}
}
catch (Exception ex) { CommonMethods.LogTime("", ex, context); }
}
但是重置后我无法使用重定向功能，因为堆栈是空的。请帮忙
让我详细说明为什么我必须通过这个小函数使用 selfredirect 函数而不是 context.wait(MessageReceived)
private async Task ApprovalConfirm(IDialogContext context, IAwaitable<IMessageActivity> result)
{
var message = await result;
if (message.Text == "no")
{
await context.PostAsync("Thank you");
context.Done(context);
}
else if (message.Text == "yes")
{
await context.PostAsync("yes");
context.Done(context);
}
else
{
context.Wait(MessageReceived);
}
}
我的用例是这样的，如果用户键入 yes，那么机器人应该返回yes，如果用户键入 no，那么机器人应该返回谢谢。 如果用户键入"Hi"，则机器人应通过 Luis 找到 Hi 的答案，这将点击新的问候语意图并返回 Hi 用户。
在这里，如果我用户上下文。等待(消息已接收)，然后机器人将简单地等待用户的下一个查询
对话框的结构！
[LuisIntent("Approval")]
public async Task Approval(IDialogContext context, LuisResult result)
{
context.ConversationData.SetValue("currentIntent", "Approval");
.
.
.
PromptDialog.Choice<string>(context, ApprovalList, ...);
}
private async Task ApprovalList(IDialogContext context, IAwaitable<string> result)
{
try
{
var request_type = await result;
.
.
context.Wait(ApprovalResponse);
}
}
catch (Exception ex)
{
CommonMethods.LogTime("ApprovalList", ex, context);
}
}
private async Task ApprovalResponse(IDialogContext context, IAwaitable<IMessageActivity> result)
{
var message = await result;
.
.
.
context.Wait(AfterApprovalComment);
}
catch (Exception ex)
{
CommonMethods.LogTime("ApprovalResponse", ex, context);
await context.PostAsync("out of approvals...");
context.Done(context);
}
}
private async Task ApprovalConfirm(IDialogContext context, IAwaitable<IMessageActivity> result)
{
var message = await result;
.
.
.
await SelfRedirect(context, context.UserData.Get<string>("CurrentQuery"), "Approval");
}
根据我们在评论中的讨论来进一步了解您的要求，您似乎不需要重置堆栈。
相反，您需要做的是利用要继承的LuisDialog中的MessageReceived方法。通过这样做，您可以直接调用该方法并强制它转到LUIS以解析新意图，而无需用户的新输入。
调用该方法与调用任何其他方法完全相同。唯一需要注意的是，由于MessageReceived方法需要IAwaitable<IMessageActivity>因此您必须创建它。好消息是，这就像使用Awaitable.FromItem一样简单