将值从控制器传递到视图

Question

我创建了一个表单，并从表单中传递了名称和图片的值。从上传控制器访问该值，如下所示：

$data = array(
'title' => $this->input->post('title', true),
'name' => $this->input->post('name',true),
'picture' => $this->file_upload($_FILES['picture'])
);
return $data;

我需要将这些值传递给视图，因此，我将上面的代码修改为：

class Upload extends CI_Controller
{
function  __construct() {
parent::__construct();
}
public function input_values(){
$data = array(
'name' => $this->input->post('name',true),
'picture' => $this->file_upload($_FILES['picture'])
);
$this->load->view('documents', $data);    }
function add(){
$data = $this->input_values();
if($this->input->post('userSubmit')) {
$this->file_upload(($_FILES['picture']));
if (!empty($_FILES['picture']['name'])) {
$config['upload_path'] = 'uploads/docs/';
$config['allowed_types'] = 'jpg|jpeg|png|gif|pdf|docx';
$config['file_name'] = $_FILES['picture']['name'];
$data['picture']=$this->file_upload($_FILES['picture']);
}
}
return $this->db->insert('files', $data);
}
//logo image upload
public function file_upload($file)
{
$this->my_upload->upload($file);
if ($this->my_upload->uploaded == true) {
$this->my_upload->file_new_name_body = 'file_' . uniqid();
$this->my_upload->process('./uploads/docs/');
$image_path = "uploads/docs/" . $this->my_upload->file_dst_name;
return $image_path;
} else {
return null;
}
}
}

但我只能得到头衔的价值。名称和标题均发生以下错误：

Message: Undefined variable: name

我从视图中访问了变量，如下所示：

<?php var_dump($title)?>
<?php var_dump($name)?
<?php var_dump($picture)?>

Answer 1

因此，这部分是您获取帖子数据和加载视图(包含上传表单(的地方

public function input_values() {
$data = array(
'name' => $this->input->post('name',true),
'picture' => $this->file_upload($_FILES['picture'])
);
$this->load->view('documents', $data);    
}

然后这部分是处理来自上传表单的 POST 请求：

function add() {
$data = $this->input_values();
if($this->input->post('userSubmit')) {
$this->file_upload(($_FILES['picture']));
if (!empty($_FILES['picture']['name'])) {
$config['upload_path'] = 'uploads/docs/';
$config['allowed_types'] = 'jpg|jpeg|png|gif|pdf|docx';
$config['file_name'] = $_FILES['picture']['name'];
$data['picture']=$this->file_upload($_FILES['picture']);
}
}
return $this->db->insert('files', $data);
}

这部分是您上传文件的地方

public function file_upload($file)
{
$this->my_upload->upload($file);
if ($this->my_upload->uploaded == true) {
$this->my_upload->file_new_name_body = 'file_' . uniqid();
$this->my_upload->process('./uploads/docs/');
$image_path = "uploads/docs/" . $this->my_upload->file_dst_name;
return $image_path;
} else {
return null;
}
}

当你调用add((函数时，它会调用input_values((函数，然后加载视图，然后不会执行下一行代码(CMIIW(。

所以，也许你想改变这个：

public function index() {
if ($this->input->post()) {
// then handle the post data and files tobe upload here
// save the post data to $data, so you will able to display them in view
} else {
// set the default data for the form
// or just an empty array()
$data = array();
}
// if the request was not a post, render view that contain form to upload file
$this->load->view('nameOfTheView', $data);
}