我正在尝试制作一个make程序,该程序允许用户右键单击网格视图中的单元格并从操作菜单中进行选择。
我有菜单显示,但我很难让信号和插槽正常工作而不会出现错误。我在Qt 5.5 C++11中工作,对Qt或C++还不是很高级,所以如果有任何帮助,将不胜感激
using namespace std;
QStandardItemModel* model;
QStandardItem *value;
MainWindow::MainWindow(QWidget *parent) :
QMainWindow(parent),
ui(new Ui::MainWindow)
{
ui->setupUi(this);
model = new QStandardItemModel(9,9,this);
ui->tableView->setModel(model);
ui->tableView->setShowGrid(true);
ui->tableView->setWordWrap(true);
//to allow menu
ui->tableView->setContextMenuPolicy(Qt::CustomContextMenu);
for(int row = 0; row < 9; row++){
ui->tableView->setRowHeight(row, 75);
for(int col = 0; col < 9; col++){
ui->tableView->setColumnWidth(col, 75);
QFont f("Consolas");
f.setPointSize(10);
value = new QStandardItem(QString("1 2 3n4 5 6n7 8 9"));
if ((row < 3 && col < 3) || (row > 5 && col < 3)
|| (row < 3 && col > 5) || (row > 5 && col > 5)
|| ((row > 2 && row < 6) && (col > 2 && col < 6))){
QBrush b(QColor("Moccasin"));
value->setBackground(b);
}
value->setFont(f);
value->setTextAlignment(Qt::AlignCenter);
model->setItem(row,col,value);
}
}
//connects model so functions run when a cell's text is changed
connect(model, SIGNAL(itemChanged(QStandardItem*)), this, SLOT(on_cell_changed(QStandardItem*)));
//this sets up the menu
connect(ui->tableView, SIGNAL(customContextMenuRequested(QPoint)), this, SLOT(menuRequest(QPoint)));
}
这是程序的主窗口部分。它(将成为)一个数独求解器,所以模型代表9x9网格,for循环用输入选项填充网格(但这不是我遇到的问题)。我需要以下菜单部分的帮助(以上只是为了上下文):
void MainWindow::menuRequest(QPoint pos)
{
QModelIndex index = ui->tableView->indexAt(pos);
std::cout << "MainWindow::menuRequest - at" << " QModelIndex row = " <<
index.row() << ", column = " << index.column() << std::endl;
QMenu menu(this);
QMenu setValues("Initialize Grid", this);
QAction *setValue1;
QAction *setValue2;
QAction *setValue3;
QAction *setValue4;
QAction *setValue5;
QAction *setValue6;
QAction *setValue7;
QAction *setValue8;
QAction *setValue9;
setValue1 = setValues.addAction("Set value to 1");
setValue2 = setValues.addAction("Set value to 2");
setValue3 = setValues.addAction("Set value to 3");
setValue4 = setValues.addAction("Set value to 4");
setValue5 = setValues.addAction("Set value to 5");
setValue6 = setValues.addAction("Set value to 6");
setValue7 = setValues.addAction("Set value to 7");
setValue8 = setValues.addAction("Set value to 8");
setValue9 = setValues.addAction("Set value to 9");
connect(menu, SIGNAL(triggered(QAction*)), this, SLOT(on_menu_clicked(QAction*)));
menu.addMenu(&setValues);
QAction *action = menu.exec(
ui->tableView->viewport()->mapToGlobal(pos));
}
void MainWindow::on_menu_clicked(QAction*){
cout << "test menu click worked";
}
MenuRequest函数中的connect语句引发错误:
connect(menu, SIGNAL(triggered(QAction*)), this, SLOT(on_menu_clicked(QAction*)));
C2664:"QMetaObject::Connection QObject::connect(const QObject*,const char*,const-char*,Qt::ConnectionType)const":无法将参数1从"QMenu"转换为"const QOobject*"
当它应该转到on_menu_click函数时,它抛出上面的错误
我知道这意味着菜单不是QObject类型的,但我不知道如何解决这个问题。如有任何帮助,将不胜感激
如注释所述,connect()函数中的第一个参数需要是指针。文件规定如下:
connect(const QObject * sender, const char * signal,
const QObject * receiver, const char * method,
Qt::ConnectionType type = Qt::AutoConnection)
http://doc.qt.io/qt-5/qobject.html#connect