我有以下下拉列表:
<select id="start" onchange="calcRoute();"></select>
我需要用从以下类型的Javascrippt数组中获得的值来填充它:
{"name":"Hotel1","address":"Bondi Beach","lat":"6.369869","lng":"80.042055","thumb_path":"img/hotel1.jpg"},{"name":"Hotel2","address":"Coogee Beach","lat":"6.025822","lng":"80.305727","thumb_path":"img/hotel2.jpg"},{"name":"Hotel3","address":"Cronulla Beach","lat":"6.691994","lng":"79.928771","thumb_path":"img/hotel3.jpg"},{"name":"Hotel4","address":"Manly Beach","lat":"6.887130","lng":"80.093420","thumb_path":"img/hotel4.jpg"},{"name":"Hotel5","address":"Maroubra Beach","lat":"7.362609","lng":"79.825005","thumb_path":"img/hotel5.jpg"}
我试了以下方法,但不起作用。
for (i = 0; i < locations.length; i++) {
$('#start select').append('<option value=' + locations[i]['name'] + '>' + locations[i]['name'] + '</option>');
alert("sdgsfg");
}
请提出解决方案。
选择器$('#start select')
将在#start
元素内选择不起作用的<select>
元素,因为select
本身的id是start
。要正确选择元素,请使用
$('#start') // or $('select#start')
最好不要弄乱HTML字符串。您可以使用Option构造函数来创建新的Option元素。
var locations = [{"name":"Hotel1","address":"Bondi Beach","lat":"6.369869","lng":"80.042055","thumb_path":"img/hotel1.jpg"},{"name":"Hotel2","address":"Coogee Beach","lat":"6.025822","lng":"80.305727","thumb_path":"img/hotel2.jpg"},{"name":"Hotel3","address":"Cronulla Beach","lat":"6.691994","lng":"79.928771","thumb_path":"img/hotel3.jpg"},{"name":"Hotel4","address":"Manly Beach","lat":"6.887130","lng":"80.093420","thumb_path":"img/hotel4.jpg"},{"name":"Hotel5","address":"Maroubra Beach","lat":"7.362609","lng":"79.825005","thumb_path":"img/hotel5.jpg"}]
var select = $('#start')[0];
locations.forEach(function(location) {
select.add(new Option(location.name, location.name));
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select id="start"></select>