我使用JPA 2.0, Hibernate 4.1.0。最后,Spring 3.1.1。RELEASE和Java 1.6。我有一个与另一个实体具有一对多关系的实体…
import javax.persistence.CascadeType;
...
@Entity
@Table(name = "classroom")
public class Classroom implements Serializable
{
...
@OneToMany(mappedBy = "classroom", cascade = {CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REMOVE})
private Set<ClassroomUser> roster;
但是,当我用一组不同的ClassroomUser对象更新我的实体时
classroom.setRoster(newRoster);
并保存实体,则保留所有先前的ClassroomUser对象。什么是正确的/最短的方式来更新我的实体,同时从数据库中删除所有孤儿记录?
谢谢,Dave
使用orphanRemoval
:
@OneToMany(mappedBy="classroom", cascade={CascadeType.ALL}, orphanRemoval=true)
无论何时从持久集中删除一个条目,它都将被删除。这意味着您需要使用持久集来处理。也就是说,你不允许替换这个集合,你应该这样做:
classroom.getRoster().clear();
classroom.getRoster().addAll(newRoster);
EXAMPLE如何同步persistent set和user required set:
/**
* Assemble ClassroomUser relations.
* @param classroom Classroom entity. Must be attached persistent or transient. Never null.
* @param userIds Collection of user identifiers. Can be empty. Never null.
*/
private void assembleClassroomUsers(Classroom classroom, Collection<Integer> userIds) {
// Make sure relation set exists (might be null for transient instance)
if (classroom.getUsers() == null) {
classroom.setUsers(new HashSet<ClassroomUser>());
}
// Create working copy of the collection
Collection<Integer> ids = new HashSet<Integer>(userIds);
// Check existing relations and retain or remove them as required
Iterator<ClassroomUser> it = classroom.getUsers().iterator();
while (it.hasNext()) {
Integer userId = it.next().getUser().getId();
if (!ids.remove(userId)) {
it.remove(); // This will be picked by the deleteOrphans=true
}
}
// Create new relations from the remaining set of identifiers
for (Integer userId : ids) {
ClassroomUser classroomUser = new ClassroomUser();
classroomUser.setClassroom(classroom);
// User must not have ClassroomUser relations initialized, otherwise Hibernate
// will get conflicting instructions what to persist and what to drop => error.
// It might be safer to use dummy transient instance...
User dummyUser = new User();
dummyUser.setId(userId);
classroomUser.setUser(dummyUser);
classroom.getUsers().add(classroomUser);
}
}
这个方法可能看起来有点复杂。您可能能够创建一些更简单的(但可能不是太多)自定义equals
/hashCode
和一些Set<E>
操作方法(例如从Guava)。