这是我的代码,它必须在代码中有+ - *
,并且必须随机选择,但它不起作用,它没有说出正确的答案。我很感激任何帮助,谢谢。
import random
import operator
question_number = 0
score = 0
ops = {'+':operator.add,
'-':operator.sub,
'*':operator.mul,
'/':operator.truediv}
number1 = random.randint(0,12)
number2 = random.randint(1,10)
op = random.choice(list(ops.keys()))
print ("this is a short maths quiz")
name = input ("what is your name")
age = input ("how old are you " +name)
print ("ok "+name+" im going to start the quiz now")
print(number1, op, number2)
user_input=int(input())
answer = (number1,op,number2)
if user_input == answer:
print("Well done")
score = score + 1
else:
print("WRONG!")
print("The answer was",answer)
question_number = question_number + 1
您需要将op
作为键,以从ops
dict和call
中获得两个数字上的适当值:
answer = ops[op](number1, number2)
您的代码正在将int与元组(即9 == (3, '+', 6)
)进行比较
除非您想要负数,否则您可能还希望将较大的数字保留在左侧,将较小的数字保持在右侧。
answer = ops[op](max(number1,number2),min(number1, number2))
此外,除非这是在一段时间内,否则循环question_number = question_number + 1
不会有太大作用。
您需要将op设为op,而不是字符串。这是您修复的代码。
import random
import operator
question_number = 0
score = 0
ops = {'+':operator.add,
'-':operator.sub,
'*':operator.mul,
'/':operator.truediv}
number1 = random.randint(0,12)
number2 = random.randint(1,10)
op = random.choice(list(ops.keys()))
print ("this is a short maths quiz")
name = input ("what is your name")
age = input ("how old are you " +name)
print ("ok "+name+" im going to start the quiz now")
print(number1, op, number2)
user_input=int(input())
if op == "+":
answer = (number1+number2)
elif op == "-":
answer = (number1-number2)
elif op == "*":
answer = (number1*number2)
elif op == "/":
answer = (number1/number2)
if user_input == answer:
print("Well done")
score = score + 1
else:
print("WRONG!")
print("The answer was",answer)
question_number = question_number + 1
您可以添加一个while
循环,使其重复