循环浏览列表，以便它为包含该项目因子的每个项目打印新列表

Question

如何修改以下代码，使其打印包含给定列表中项目因子的单独列表？

n = [3,4,5]
for i in n:
print('Factors of ', i)
for j in range(1,i+1):
if i%j == 0:
print(j)

Answer 1

我会选择一个简单的factors函数，然后执行循环

def factors(n):
"""Not the most optimal solution"""
return [i for i in range(1, n+1) if not n % i]
n = [3, 4, 5]
for i in n:
print(f'Factors of {i} = {factors(i)}')

输出

Factors of 3 = [1, 3]
Factors of 4 = [1, 2, 4]
Factors of 5 = [1, 5]

Answer 2

我已经重构了你的代码，使其更具可读性和易于理解：

n = [3, 4, 5]
def get_factors(num):
result = []
for i in range(1, num+1):
if num % i == 0:
result.append(i)
return result
print([get_factors(elem) for elem in n])

让我知道这是否回答了您的问题？

Answer 3

这对我有用：

n = [3,4,5]
for i in n:
print('Factors of ', i)
remaining = i
while remaining > 1 :
for j in range(2,remaining+1):
if remaining%j == 0:
print(j)
remaining /= j

结果：

('Factors of ', 3)
3
('Factors of ', 4)
2
2
('Factors of ', 5)
5
>>> 

巧合的是，它的工作原理类似于 Linux 命令factor：

$ factor 3 4 5
3: 3
4: 2 2
5: 5