我正在编写一个程序,向用户返回 3 个字母字符串的所有可能组合的列表,以便在弹出窗口中输入 3 位电话号码。算法代码是完美的,我不需要帮助。唯一的问题是向用户返回错误消息。为空白输入返回错误消息的代码很好。当用户输入无效字符(不是 2、3、4、5、6、7、8 或 9)时,除非他们的整个输入都是无效字符,否则它不会返回错误消息。例如,如果我输入 123,当字符串中的唯一字符"1"无效时,错误窗口不会弹出。但是,如果我输入"111"(所有字符都无效),则会显示错误消息。如果用户在并非所有字符都无效的情况下输入了无效字符,我想返回错误窗口。示例:输入 123,应给用户一个错误窗口。
import javafx.application.Application;
import javafx.geometry.Pos;
import javafx.geometry.HPos;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.Label;
import javafx.scene.control.TextField;
import javafx.scene.layout.GridPane;
import javafx.stage.Stage;
import javafx.scene.text.*;
import javafx.scene.control.Alert;
import javafx.scene.control.Alert.AlertType;
public class Runner extends Application
{
private TextField input = new TextField();
private Button outputButton = new Button("Get all possible mnemonics");
@Override
public void start(Stage primaryStage)
{
GridPane gridPane = new GridPane();
gridPane.setHgap(5);
gridPane.setVgap(5);
Text sceneMenu = new Text("Phone digits:n" + "----------n" + "0: No lettersn" + "1: No lettersn" +
"2: ABCn" + "3: DEFn" + "4: GHIn" + "5: JKLn" + "6: MNOn" + "7: PQRSn" +
"8: TUVn" + "9: WXYZn");
sceneMenu.setFont(Font.font("Arial", FontWeight.BOLD, 16));
gridPane.add(sceneMenu, 5, 0, 1, 10);
gridPane.add(new Label("Enter your three digit phone number:"), 0, 0);
gridPane.add(input, 1, 0);
gridPane.add(outputButton, 1, 7);
gridPane.setAlignment(Pos.CENTER);
input.setAlignment(Pos.BOTTOM_RIGHT); Textbox.
GridPane.setHalignment(outputButton, HPos.RIGHT);
outputButton.setOnAction(e -> {
String theInput = input.getText();
if (theInput.isEmpty())
{
Alert error1 = new Alert(AlertType.ERROR);
error1.setTitle("Blank input");
error1.setHeaderText("BLANK INPUT!");
error1.setContentText("Please enter a three digit number.");
error1.showAndWait();
}
else
{
String [] matches = new String[]{"2", "3", "4", "5", "6", "7", "8", "9"};
for (String s : matches)
{
if (theInput.contains(s)== false)
{
Alert error2 = new Alert(AlertType.ERROR);
error2.setTitle("Invalid digit");
error2.setHeaderText("INVALID DIGIT!");
error2.setContentText("Please enter three digits ranging from 2 through 9");
error2.showAndWait();
break;
}
else
{
calculateMnemonics();
break;
}
}
}
});
Scene scene = new Scene(gridPane, 700, 600);
primaryStage.setTitle("Customer order");
primaryStage.setScene(scene);
primaryStage.show();
}
private void calculateMnemonics()
{
String theInput = input.getText();
Calculator calc = new Calculator(theInput);
Alert outputWindow = new Alert(AlertType.INFORMATION);
outputWindow.setTitle("Mnemonic list");
outputWindow.setHeaderText("Your mnemonic list for your numbers");
outputWindow.setContentText(calc.printMnemonics());
outputWindow.showAndWait();
}
public static void main(String[]args)
{
launch(args);
}
}
import java.util.List;
import java.util.LinkedList;
import java.util.Arrays;
public class Calculator
{
private String inputtedNumbers;
public Calculator()
{
this("");
}
public Calculator(String inputtedNumbers)
{
this.inputtedNumbers = inputtedNumbers;
}
public String getInputtedNumbers()
{
return inputtedNumbers;
}
public void setInputtedNumbers(String inputtedNumbers)
{
this.inputtedNumbers = inputtedNumbers;
}
public List<String> listMnemonics(String digits)
{
String[] letters = {"ABC", "DEF", "GHI", "JKL", "MNO", "PQRS", "TUV", "WXYZ"};
List<String> rec = new LinkedList<>();
StringBuilder string = new StringBuilder();
listMnemonics(digits, 0, letters, string, rec);
return rec;
}
private void listMnemonics(String digits, int number, String[] letters, StringBuilder string, List<String> rec)
{
if (digits.length() == number)
{
rec.add(string.toString());
return;
}
String letter = letters[digits.charAt(number) - '2'];
for (int i = 0; i < letter.length(); i++)
{
string.append(letter.charAt(i));
listMnemonics(digits, number + 1, letters, string, rec);
string.deleteCharAt(string.length() - 1);
}
}
public String printMnemonics()
{
Calculator o = new Calculator();
List<String> list1 = o.listMnemonics(inputtedNumbers);
String [] stringArray = list1.toArray(new String[0]);
return Arrays.toString(stringArray);
}
}
以下应该可以解决问题
if (!theInput.matches("[2-9]+"))
{
Alert error2 = new Alert(AlertType.ERROR);
error2.setTitle("Invalid digit");
error2.setHeaderText("INVALID DIGIT!");
error2.setContentText("Please enter three digits ranging from 2 through 9");
error2.showAndWait();
}
else
{
calculateMnemonics();
}
此解决方案使用正则表达式(简称正则表达式)。它测试提供的String
是否与2
中的任何字符匹配 - 9
一次或多次(这就是+
正在做的事情)
这甚至会检查输入是否为空,所以如果你愿意,你可以放弃单独的空性检查。如果您不希望它检查空性,则可以使用 !theInput.matches("[2-9]*")
作为检查前一部分是否存在零次或多次的*
。