用C将内存打印为1字节十六进制

Question

您能帮我解决以下C问题吗?我试图打印30个连续值的列表，从某个内存地址开始。我想打印1字节作为十六进制每个内存位置。作为要插入哪个内存地址的指示，我在程序开始时打印一个虚拟地址。

问题是我得到的值大于1字节。对于长序列的零，这仍然是00，但一旦非零值出现，我得到一个4字节的"窗口"的打印。这会产生以下输出:

Main function address is 0x8048494 
Dummy variable address is 0x9a2e008 
Enter the address (without the 0x):9a2e008
You entered: 9a2e008 
Address     Byte value 
0x9a2e008   00 
0x9a2e009   00 
0x9a2e00a   00 
0x9a2e00b   00 
0x9a2e00c   00 
0x9a2e00d   00 
0x9a2e00e   00 
0x9a2e00f   00 
0x9a2e010   00 
0x9a2e011   f1000000 
0x9a2e012   ff10000     
0x9a2e013   20ff100 
0x9a2e014   20ff1 
0x9a2e015   3900020f 
0x9a2e016   61390002 
0x9a2e017   32613900 
0x9a2e018   65326139 
0x9a2e019   30653261 
0x9a2e01a   30306532 
0x9a2e01b   38303065 
0x9a2e01c   383030 
0x9a2e01d   3830 
0x9a2e01e   38 
0x9a2e01f   00 
0x9a2e020   00 
0x9a2e021   00 
0x9a2e022   00 
0x9a2e023   00 
0x9a2e024   00 
0x9a2e025   00

目前为止我的代码是:

#include <assert.h>
#include <stdio.h>
#include <stdlib.h>
#define NUMBER_OF_BYTES 10
void showAddresses(void);
void printMemoryAtAddress(void);
int * dummy;                                    
int dumpSize = 30;                                          
int main(void)
{
    dummy = (int *) malloc     (sizeof(int));                                       showAddresses();                                        
    printMemoryAtAddress();
    return 0;
}
void showAddresses(void)
{
    printf("Main function address is %p n", main);
    printf("Dummy variable address is %p n",(void*)dummy);
}
void printMemoryAtAddress(void)
{
    int input;
    printf("Enter the address (without the 0x):");
    scanf("%x", &input);
    printf("You entered: %x n", input);
    printf("Address tByte value n");
    int i;
    for(i=0;i<dumpSize;i++)
    {
        int* address;
        address = (int*) (input+i);
        printf("%p t", address);   
        printf("%.2x n", *address);                                        
    }
}

对于这个问题的任何帮助都将非常感激!如果这个问题很愚蠢，我道歉。(我还在学习，经过几个小时的尝试，似乎找不到解决方案!)乔

Answer 1

你的问题在这里:

void printMemoryAtAddress(void)
{
    int input;
    printf("Enter the address (without the 0x):");
    scanf("%x", &input);
    printf("You entered: %x n", input);
    printf("Address tByte value n");
    int i;
    for(i=0;i<dumpSize;i++)
    {
        int* address;
        address = (int*) (input+i);
        printf("%p t", address);   
        printf("%.2x n", *address);                                        
    }
}

address应该是unsigned char*而不是int*。作为int*类型，它像读取整数一样读取内存，您希望它被读取为只有一个字节的char类型。

祝你好运!