在数组中存储多个用户输入

Question

该程序将询问用户学生姓名和成绩，然后同时显示两者。用户输入的值存储在数组名称和数组等级中。我使用计数器控制的 for 循环将用户输入收集到数组中。如果我想为每个学生输入多个成绩怎么办？编程相当新手，任何关于如何做到这一点的输入或想法将不胜感激......

public class Five {
public static void main(String[] args) {
    int students;
    Scanner input = new Scanner(System.in); //created input scanner

System.out.println("How many students are on your roster? If you wish to exit please type 00: ");// Initializing statement for program************
students = input.nextInt();
       if(students == 00) { //Exit program****************
       System.out.println("Maybe Next Time!!");
           System.exit(0);
         }
String[] names = new String[students];// Array names*******
String[]grade = new String[students]; //Array grade********
// Use Counter to go through Array**************************
        for(int counter =0; counter < students; counter++){
        System.out.println("Enter the name of a student: " +  (counter +1));
        names [counter] = input.next();
        System.out.println("Now enter that students grade A, B, C, D OR F: ");
        grade [counter] = input.next();
        }
input.close();// End Scanner object
//Use For loop for Printing names and grades entered by the user**************
System.out.println("Your students names and grades are as follows: ");
        for(int counter =0; counter < students; counter++){
        System.out.println("Name: " + names[counter]);
        System.out.println("Grade: " + grade[counter]);
        }
    }
}

Answer 1

您可以使用不规则数组来输入多个成绩您需要声明它，因此这里有一种方法可以做到这一点。

    String[] names = new String[students];// Array names*******
    String[][]grade = new String[names][]; //Array grade********
      for(int i=0; i<names[i];i++)
  {System.out.println("How many grades will you enter for "+names[i]+"?")
   int temp=input.nextInt();
  for(int j=0; j<names[i][temp-1];j++){
  grad[i][j]=input.next();         
           }}

Answer 2

您可能应该创建一个学生类和一个成绩类并将它们存储为对象。使用数据结构，您最好的选择是哈希图。

HashMap<String, List<String>> grades = new HashMap<>();
grades.put("Jack", new ArrayList<>());
grades.get("Jack").add("A");

你可以在这里找到更多关于HashMap的信息