我正在尝试根据表单的子网格值启用和禁用自定义功能区按钮。我创建了一个简单的Java脚本方法作为web资源,并使用工作台在Enable规则中调用它。下面是我的代码:
function DisableSendInvitationRibbonButton()
{
alert('test');
var gridControl = document.getElementById("Attendees").control;
if (gridControl.readyState != "complete")
{ alert('readyState not Complete');
// delay one second and try again.
setTimeout(DisableSendInvitationRibbonButton, 100);
return;
}
else
{ alert('readyState Complete');
var ids = gridControl.get_allRecordIds();
alert(ids.length);
}
}
代码只点击了警报"测试",看起来子网格没有加载。如有任何帮助,我们将不胜感激。
谢谢!
很可能您有一些空的var,但您没有控制它。请尝试下面的代码,看看问题出在哪里。
function DisableSendInvitationRibbonButton()
{
alert('test');
var myGrid = document.getElementById("Attendees");
if(myGrid == null) {
alert('myGrid is null');
return;
}
var gridControl = myGrid.control;
if(gridControl == null) {
alert('gridControl is null');
return;
}
if (gridControl.readyState != "complete")
{ alert('readyState not Complete');
// delay one second and try again.
setTimeout(DisableSendInvitationRibbonButton, 100);
return;
}
else
{ alert('readyState Complete');
var ids = gridControl.get_allRecordIds();
alert(ids.length);
}
}
感谢大家的回复,我能够解决这个问题,我注意到的主要问题是,您必须在更改事件时调用Grid,并将所有逻辑放在那里。下面是我更新的代码:
function ShareMOM()
{
var subGridId = "ActionItems";
var grid = document.getElementById(subGridId);
if( grid != null)
{
var val = ReadSelectedSubGridRecords();
return val;
}
else
{
return false;
}
}
function ReadSelectedSubGridRecords()
{
if (document.getElementById('ActionItems'))
{
var grid = document.getElementById('ActionItems').control;
var ids = grid.get_allRecords();
if (ids.length > 0)
{
return true;
}
else
{
return false;
}
}
}