从 url 下载文件并将其上传到 AWS S3 而不保存 - node.js

Question

我正在编写一个应用程序，该应用程序从 url 下载图像，然后使用 aws-sdk 将其上传到 S3 存储桶。

以前我只是下载图像并像这样将它们保存到磁盘。

request.head(url, function(err, res, body){
    request(url).pipe(fs.createWriteStream(image_path));
});

然后像这样将图像上传到 AWS S3

fs.readFile(image_path, function(err, data){
    s3.client.putObject({
        Bucket: 'myBucket',
        Key: image_path,
        Body: data
        ACL:'public-read'
    }, function(err, resp) {
        if(err){
            console.log("error in s3 put object cb");
        } else { 
            console.log(resp);
            console.log("successfully added image to s3");
        }
    });
});

但是我想跳过将图像保存到磁盘的部分。有没有办法pipe request(url)的响应到变量，然后上传？

Answer 1

这里有一些JavaScript可以很好地做到这一点：

    var options = {
        uri: uri,
        encoding: null
    };
    request(options, function(error, response, body) {
        if (error || response.statusCode !== 200) { 
            console.log("failed to get image");
            console.log(error);
        } else {
            s3.putObject({
                Body: body,
                Key: path,
                Bucket: 'bucket_name'
            }, function(error, data) { 
                if (error) {
                    console.log("error downloading image to s3");
                } else {
                    console.log("success uploading to s3");
                }
            }); 
        }   
    });

Answer 2

这就是我所做的并且效果很好：

const request = require('request-promise')
const AWS = require('aws-sdk')
const s3 = new AWS.S3()
const options = {
    uri: uri,
    encoding: null
};
async load() {
  const body = await request(options)
  
  const uploadResult = await s3.upload({
    Bucket: 'bucket_name',
    Key   : path,
    Body  : body,   
  }).promise()
  
}

Answer 3

这样的事情呢：

const stream = require('stream');
const request = require('request');
const s3 = new AWS.S3()
const pass = new stream.PassThrough();
request(url).pipe(pass);
s3.upload({
    Bucket: 'bucket_name',
    Key: path,
    Body: pass,
});

Answer 4

import axios from "axios";
import aws from 'aws-sdk'
import crypto from 'crypto'
const s3 = new aws.S3();
export const urlToS3 = async ({ url, bucket = "rememoio-users", key = Date.now() + crypto.randomBytes(8).toString('hex') + ".png" }) => {
  try {
    const { data } = await axios.get(url, { responseType: "stream" });
    const upload = await s3.upload({
      Bucket: bucket,
      ACL: 'public-read',
      Key: key,
      Body: data,
    }).promise();
    return upload.Location;
  } catch (error) {
    console.error(error);
    throw new Error;
  }
};

Answer 5

你可以像这样用Axios实现。有关详细信息，请参阅此内容。

const axios = require("axios");
const AWS = require("aws-sdk");
const { PassThrough } = require("stream");
const s3 = new AWS.S3({
  accessKeyId: "accessKeyId",
  secretAccessKey: "accessKey",
  region: "region",
});
const bucket = "BucketName";
const key = "key";
const uploadToS3 = async (bucket, key) => {
  try {
    const stream = await axios.get(url, { responseType: "stream" });
    const passThrough = new PassThrough();
    const response = s3.upload({ Bucket: bucket, Key: key, Body: passThrough });
    stream.data.pipe(passThrough);
    return response.then((data) => data.Location).catch((e) => console.error(e));
  } catch (error) {
    console.error(error);
  }
};
uploadToS3(bucket, key);

Answer 6

使用 fetch：

//fetch image from url
const imageResp = await fetch(
    '<image url>'
)
// transform to arrayBuffer
const imageBinaryBuffer = Buffer.from(await imageResp.arrayBuffer())
//get image type
const imageType = imageName.toLowerCase().includes(".png")
    ? "image/png"
    : "image/jpg";
//get presigned url and data [this can be different on your end]
const presignedResponse = await getPresignedURL(imageBinaryBuffer, imageName, imageType)
const s3Result = presignedResponse.data
// build the formData 
let formData = new FormData()
Object.keys(s3Result.fields).forEach(key => {
    formData.append(key, s3Result.fields[key]);
});
formData.append("file", imageBinaryBuffer);
const s3resp = await fetch(s3Result.url, {
    method: "POST",
    body: formData,
});
return s3resp.headers.location