增加请求/第二次Python Google地图地理编码器

Question

我很难通过Google Maps GeoCoder增加每秒的要求。我使用的是一个付费帐户（以$ .50/1000的要求），因此根据Google GeoCoder API，我应该能够每秒最多弥补50个请求。

我有一个15K地址的列表，我正在尝试获得GPS坐标。我将它们存储为熊猫的数据框架，并在它们上循环。为了确保这不是由于循环缓慢而引起的，我测试了它在所有15K上循环的速度，而仅需1.5秒。但是我只能每秒提出少于1个请求。我意识到这可能是由于我的互联网连接慢，所以我用明显快速的互联网启动了Windows Google Cloud VM。我能够将请求加快到约1.5请求/秒，但在理论上仍然慢。

我认为这可能是由于使用Python库地理编码器，因此我尝试使用Python请求直接提出请求，但这也没有加快速度。

这与我不使用服务器的事实有关吗？我认为这没关系，因为我正在使用Google Cloud VM。另外，我知道这与多线程无关，因为它已经可以使用1个核心以极高的速度通过循环迭代。事先感谢您的想法。

import geocoder
import pandas as pd
import time
import requests

startTime = time.time()
#Read File Name with all transactions up to October 4th
input_filename = "C:/Users/username/Downloads/transaction-export 10-04-2017.csv"
df = pd.read_csv(input_filename, header=0, error_bad_lines=False)
#Only look at customer addresses
df = df['Customer Address']
#Drop duplicates and NAs
df = df.drop_duplicates(keep='first')
df = df.dropna()
#convert dataframe to string
addresses = df.tolist()
#Google Api Key
api_key = 'my_api_key'
#create empty array
address_gps = []
#google api address
url = 'https://maps.googleapis.com/maps/api/geocode/json'
#For each address return its geocoded latlng coordinates
for int, val in enumerate(addresses):
    ''' Direct way to make call without geocoder
    params = {'sensor': 'false', 'address': address, 'key': api_key}
    r = requests.get(url, params=params)
    results = r.json()['results']
    location = results[0]['geometry']['location']
    print location['lat'], location['lng']
    num_address = num_address+1;
    '''
    endTime = time.time()
    g = geocoder.google(val, key=api_key,  exactly_one=True)
    print "Address,", (val), "Number,", int, "Total,", len(addresses), "Time,", endTime-startTime
    if g.ok:
        address_gps.append(g.latlng)
        print g.latlng
    else:
        address_gps.append(0)
        print("Error")
    #save every 100 iterations
    if int%100==0:
        # save as csv
        df1 = pd.DataFrame({'Address GPS': address_gps})
        df1.to_csv('C:/Users/username/Downloads/AllCustomerAddressAsGPS.csv')

# save as csv
df1 = pd.DataFrame({'Address GPS': address_gps})
df1.to_csv('C:/Users/username/Downloads/AllCustomerAddressAsGPS.csv')

Answer 1

提高此速度的一种方法是维护与Google的请求会话，而不是使用每个请求创建新的会话。这是在geocoder文档中建议的。

您的修改代码将是：

import requests
#Google Api Key
api_key = 'my_api_key'
#create empty array
address_gps = []
#google api address
url = 'https://maps.googleapis.com/maps/api/geocode/json'
#For each address return its geocoded latlng coordinates
with requests.Session() as session:
    for int, val in enumerate(addresses):
        ''' Direct way to make call without geocoder
        params = {'sensor': 'false', 'address': address, 'key': api_key}
        r = requests.get(url, params=params)
        results = r.json()['results']
        location = results[0]['geometry']['location']
        print location['lat'], location['lng']
        num_address = num_address+1;
        '''
        endTime = time.time()
        g = geocoder.google(val, key=api_key,  exactly_one=True, session=session)
        print "Address,", (val), "Number,", int, "Total,", len(addresses), "Time,", endTime-startTime
        if g.ok:
            address_gps.append(g.latlng)
            print g.latlng
        else:
            address_gps.append(0)
            print("Error")
        #save every 100 iterations
        if int%100==0:
            # save as csv
            df1 = pd.DataFrame({'Address GPS': address_gps})
            df1.to_csv('C:/Users/username/Downloads/AllCustomerAddressAsGPS.csv')
# save as csv
df1 = pd.DataFrame({'Address GPS': address_gps})
df1.to_csv('C:/Users/username/Downloads/AllCustomerAddressAsGPS.csv')