Onmouseover and timeout on javascript

Question

我有这个id在我的html代码:

<div id="me">
<img src="Me.JPG" alt="Me" width="450" height="450" alt="picture" align="right"/>
</div>

如何在鼠标停留在图片上后每3秒更换一次图片，

和回到原来的图片一旦鼠标出来?

Answer 1

您可以创建一个函数，每3秒更改一次图像。然后，当您将鼠标移到图像上时，调用该函数并启动计时器。当鼠标离开图像时，清除计时器。

var img = document.getElementById( "me" ).getElementsByTagName( "img" )[0];
var images = ["Me.JPG", "new image path", "..."];
var i = 1;
var timer;
function change() {
    img.src = images[i];
    if ( ++i >= images.length ) {
        i = 0;
    }
    timer = setTimeout( change, 3000 );
}
img.onmouseover = function() {
    timer = setTimeout( change, 3000 );
};
img.onmouseout = function() {
    img.src = images[0];
    clearTimeout( timer );
};

Answer 2

这里有一个JsFiddle快速解决方案的链接:http://jsfiddle.net/jJBEu/2/

var img = document.getElementById('me').getElementsByTagName('img')[0],
    index = 0,
    sources = [
        'http://icons.iconarchive.com/icons/iconka/social-treat/128/yumtube-icon.png',
        'http://icons.iconarchive.com/icons/iconka/social-treat/128/sweeter-icon.png',
        'http://icons.iconarchive.com/icons/iconka/social-treat/128/facebow-icon.png'
    ],
    timer;
img.addEventListener('mouseover', swapImages, false);
img.addEventListener('mouseout', function(){
    clearTimeout(timer);
    img.src = sources[0];
}, false);
function swapImages(event, setindex){
    index = index == (sources.length - 1) ? 0 : index + 1;
    timer = setTimeout(function(){
        img.src = sources[index];
        swapImages();
    }, 3000);
}

编辑修复一个愚蠢的错误，我检查数组索引长度没有减去1。

Answer 3

html:

<img src="Me.JPG" alt="Me" width="450" height="450" alt="picture" align="right"
 onmouseover="animate(this)" onmouseout="stopanimation()" />

javascript:

/* globals */
var animTimer = null;
var animImg = null; 
var images = [new Image(), new Image(), new Image(), new Image(), new Image(),new Image()];
var imgIndex = 0;    
/* pre-load images in browser cash */
images[0].src = "Me.JPG";
images[1].src = "anim1.gif";
images[2].src = "anim2.gif";
images[3].src = "anim3.gif";
images[4].src = "anim4.gif";
images[5].src = "anim5.gif";
/* animation  */
function animate(img){
   if (typeof img != 'undefined'){animImg = img;}
   imgIndex += 1;
   if (imgIndex>images.length-1){imgIndex=1;}
   animImg.src=images[imgIndex].src; 
   animTimer = setTimeout(animate, 3000);
}
function stopanimation(){
   clearInterval(animTimer);
   animImg.src = images[0].src; 
}

Answer 4

就像，只给myImg的img和id(或任何你想要的):

var img_arr = ["img1.png", "img2.png", "img3.png"],
    img_index = 0,
    interval_id = 0,
    div = document.getElementById("me"),
    img = document.getElementById("myImg");
div.onmouseover = function () {
    interval_id = window.setInterval(function () {
        if (img_index === (img_arr.length - 1)) {
            img_index = 0;
        }
        img.src = img_arr[img_index++];
    }, 3000);
};
div.onmouseout = function () {
    window.clearInterval(interval_id);
};