谷歌大查询，我在使用'unnest'函数时丢失了空行

Question

#StandardSQL
WITH tableA AS (
SELECT ["T001", "T002", "T003"] AS T_id, [1, 5] AS L_id
UNION ALL
SELECT ["T008", "T009"] AS T_id, NULL AS L_id
)
SELECT * FROM tableA, UNNEST(L_id) AS unnest

当我执行此代码时，我期望结果如下。

RowNumber  T-id            L-id  unnest
1          T001,T002,T003  1,5   1
2          T001,T002,T003  1,5   5
3          T004,T005       NULL  NULL

但我得到的结果是：

RowNumber  T-id            L-id  unnest
1          T001,T002,T003  1,5   1
2          T001,T002,T003  1,5   5

我输了第三排。 然后，我看到了谷歌的官方文档，其中指出了以下内容：

UNNEST treats NULL as follows.
・NULL and empty ARRAY generate zero rows.
・An ARRAY containing NULL generates a row containing a NULL value.

但我不想丢失我的空行。

如何保留空行？

请告诉我解决方案...

Answer 1

不要使用CROSS JOIN，而是使用 LEFT JOIN。这将返回空数组的空值行。您可能还对文档中的使用数组主题感兴趣。

#StandardSQL
WITH tableA AS (
SELECT ["T001", "T002", "T003"] AS T_id, [1, 5] AS L_id
UNION ALL
SELECT ["T008", "T009"] AS T_id, NULL AS L_id
)
SELECT * FROM tableA
LEFT JOIN UNNEST(L_id) AS value;