基于字符串数组"with partial match"筛选对象数组

Question

>我有一个对象数组，想根据另一个字符串数组的值对其进行过滤，并删除不包含任何字符串的对象。

我尝试对字符串数组使用 split 并在 forEach 中搜索每个术语，但它不起作用，然后尝试了以下用作过滤器的方法，但它过滤了完全匹配而不是部分匹配。

var employees = [
{"name": "zxc asd", "age":"30"},
{"name": "asd", "age":"24"},
{"name": "qwe", "age":"44"},
{"name": "zxc", "age":"28"},
];
var keepNames = ["asd", "qwe"];
keepNames = keepNames.map(name => {
return name.toLowerCase();
});
var filteredEmployees = employees.filter(emp => {
return keepNames.indexOf(emp.name.toLowerCase()) !== -1;
});
console.log( filteredEmployees );

Expected Output[  
{"name": "zxc asd", "age":"30"},
{"name": "asd", "age":"24"},
{"name": "qwe", "age":"44"}];
Actual Output [
{"name": "asd", "age":"24"},
{"name": "qwe", "age":"44"}]

我真的很感激任何帮助。 提前致谢

Answer 1

您还需要使用名称keep迭代数组并检查值。

var employees = [{ name: "zxc asd", age: "30" }, { name: "asd", age: "24" }, { name: "qwe", age: "44" }, { name: "zxc", age: "28" }],
keep = ["asd", "qwe"],
filtered = employees.filter(({ name }) =>
keep.some(n => name.toLowerCase().includes(n))
);
console.log(filtered);

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Answer 2

indexOf使用strict equality，因此它不会部分匹配。

您可以使用some和includes

var employees = [ {"name": "zxc asd", "age":"30"},{"name": "asd", "age":"24"},{"name": "qwe", "age":"44"},{"name": "zxc", "age":"28"},];
var filterBy = ["asd", "qwe"];
var filteredEmployees = employees.filter(emp => {
return filterBy.some(v => emp.name.toLowerCase().includes(v.toLowerCase()))
});
console.log(filteredEmployees);