我有一个带有多个JSON对象的数组。表中的任何JSON数组中的最大元素数为8。
这是数组原始值的示例:
variants
----------------------------------------------------------------
[
{
"id": 12388362846279,
"inventory_quantity": 10,
"sku": “sku1”
},
{
"id": 12388391387207,
"inventory_quantity": 31,
"sku": “sku2”
},
{
"id": 12394420142151,
"inventory_quantity": 12,
"sku": “sku3”
},
{
"id": 12394426007623,
"inventory_quantity": 4,
"sku": “sku4”
},
{
"id": 12394429022279,
"inventory_quantity": 9,
"sku": “sku5”
},
{
"id": 12394431414343,
"inventory_quantity": 15,
"sku": “sku6”
},
{
"id": 12394455597127,
"inventory_quantity": 22,
"sku": “sku7”
},
{
"id": 12394459856967,
"inventory_quantity": 0,
"sku": “sku8”
}
]
我的查询试图平坦并解析数组以返回每个对象的一行:
select
variants[0]:sku,
variants[0]:inventory_quantity,
variants[1]:sku,
variants[1]:inventory_quantity,
variants[2]:sku,
variants[2]:inventory_quantity,
variants[3]:sku,
variants[3]:inventory_quantity,
variants[4]:sku,
variants[4]:inventory_quantity,
variants[5]:sku,
variants[5]:inventory_quantity,
variants[6]:sku,
variants[6]:inventory_quantity,
variants[7]:sku,
variants[7]:inventory_quantity
from table
, lateral flatten(input => variants)
但是,我的输出正在返回重复/重复值:
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
| sku1 | 10 | sku2 | 31 | sku3 | 12 | sku4 | 4 | sku5 | 9 | sku6 | 15 | sku7 | 22 | sku8 | 0 |
+------+----+------+----+------+----+------+---+------+---+------+----+------+----+------+---+
我希望我的输出看起来类似于以下内容:
+------+----+
| sku1 | 10 |
+------+----+
| sku2 | 31 |
+------+----+
| sku3 | 12 |
+------+----+
| sku4 | 4 |
+------+----+
| sku5 | 9 |
+------+----+
| sku6 | 15 |
+------+----+
| sku7 | 22 |
+------+----+
| sku8 | 0 |
+------+----+
使用横向平坦的
消除了您明确引用数组位置的需求。阵列的每个成员成为其自己的行。因此,要获取您想要的结果,只需使用:
select v.value:sku::varchar,
v.value:inventory_quantity
from table,
lateral flatten(input => table.variants) v
;
如果从表中有一些列,这些列位于您要在每行中引用的数组之外,则只需将它们包含在Select中即可。本质上,来自数组的扁平行被"连接"到表的非巢列中,隐式...