"Static polymorphism with Qt signal/slot: What is wrong?"

Question

我正在尝试使用静态多态性，而不是Qt信号/插槽机制的动态多态性。但我得到了编译错误。我的代码出了什么问题？什么是变通方法？

设备.h

#ifndef DEVICES_H
#define DEVICES_H
#include <QtCore>
#include <qdebug.h>
class DeviceController : public QObject
{
Q_OBJECT
public:
explicit DeviceController(QObject *parent = nullptr):QObject(parent){}
virtual ~DeviceController() {}
void doAllDevicesInit(){
emit deviceAInitSignal();
}
signals:
void deviceAInitSignal();
};
template<typename T> class BaseDevice  {
public:
void init() {
static_cast<T*>(this)->doInit();
qDebug() << QString("BaseDevice initialized!");
}
};
class DeviceA : public BaseDevice<DeviceA> {
public:
void doInit() {
qDebug() << "DeviceA initialized!";
}
};
#endif // DEVICES_H

main.cpp

#include "devices.h"
int main(int argc, char *argv[])
{
Q_UNUSED(argc);Q_UNUSED(argv);
DeviceA deviceA;
DeviceController deviceController;
QObject::connect(&deviceController,&DeviceController::deviceAInitSignal,
&deviceA, &DeviceA::init);
deviceController.doAllDevicesInit();
return 0;
}

编译输出

Qt5.12.2/5.12.2/gcc_64/include/QtCore/qobjectdefs_impl.h:414:94:错误：从类型"QObject*"到类型的static_cast无效'QtPrivate:：FunctionPointer:：*)()>：：Object*'｛又名"BaseDevice*"｝FuncType:：模板调用(static_cast(this_)->函数，static_cast(r)，a)；

Answer 1

感谢drescherjm的评论，解决方法如下

设备.h

...
template<typename T> 
class BaseDevice: public QObject  {
//Q_OBJECT, Error: Template classes not supported by Q_OBJECT
public:
explicit BaseDevice(QObject *parent = nullptr):QObject(parent){}
virtual ~BaseDevice() {}
void init() {
static_cast<T*>(this)->doInit();
qDebug() << QString("BaseDevice initialized!");
}
};
class DeviceA : public BaseDevice<DeviceA> {
Q_OBJECT
public:
explicit DeviceA(QObject *parent = nullptr):BaseDevice<DeviceA>(parent){}
virtual ~DeviceA() {}
void doInit() {
qDebug() << "DeviceA initialized!";
}
};
#endif // DEVICES_H