使用scipy.integrate.trapz进行数值积分会返回结果,但scipy.inintegrate.simps不



我正在尝试用数字集成以下数据:

t,y
9.960000000000001e-05,8.334379999999999e-05
9.98e-05,0.000126125
0.0001,0.00018125
0.0001002,0.0002385
0.00010040000000000001,0.000289625
0.0001006,0.000347313
0.0001008,0.000391719
0.000101,0.00043284399999999994
0.00010120000000000001,0.000472375
0.00010140000000000001,0.000502469
0.00010160000000000002,0.000528594
0.00010180000000000001,0.000546219
0.000102,0.000569188
0.0001022,0.000584719
0.0001024,0.000593969
0.00010260000000000001,0.000607375
0.0001028,0.000618906
0.000103,0.000629344
0.0001032,0.000629344
0.0001034,0.000636313
0.00010360000000000001,0.0006374999999999999
0.0001038,0.000630375
0.00010400000000000001,0.00059875
0.0001042,0.00046825
0.0001044,0.000287344
0.00010460000000000002,0.000208594
0.0001048,0.000196094
0.000105,0.000172625
0.00010520000000000001,0.000134781
0.0001054,0.000115906
0.0001056,0.00010306300000000001
0.00010580000000000001,9.31563e-05

如下所示,我从csv文件中读取了此数据集。这是我的代码:

import pandas as pd
from scipy.integrate import trapz, simps
root="my/root/dir"
df = pd.read_csv(root+r"simps.csv")
print(trapz(df["t"], df["y"]))
print(simps(df["t"], df["y"]))

trapz返回一个值(-9.5865055e-10(,而simps返回nan和以下错误:

anacondapathscipyintegratequadrature.py:324: RuntimeWarning: divide by zero encountered in true_divide
h0divh1 = h0 / h1
anacondapathscipyintegratequadrature.py:326: RuntimeWarning: divide by zero encountered in true_divide
y[slice1]*hsum*hsum/hprod +
anacondapathscipyintegratequadrature.py:327: RuntimeWarning: invalid value encountered in add
y[slice2]*(2-h0divh1))
anacondapathscipyintegratequadrature.py:326: RuntimeWarning: invalid value encountered in add
y[slice1]*hsum*hsum/hprod +

为什么会出现此错误?

一个非常愚蠢的错误:我交换了x和y。Simps需要y作为的第一个参数

最新更新