我可以在Microsoft Lync API的哪个位置为传入的im设置事件处理程序

Question

我正在为instantmessagerreceived事件设置一个处理程序，但它似乎只在传出的文本消息上触发，而不是传入的。下面是我正在运行的代码:

# Register the app with Growl
$icon = "https://docs.google.com/uc?export=download&id=0B1Weg9ZlwneOZmY2b1NSVXJ0Q2s"
$types = '"new-im","new-call","invitation","share"'
& 'C:Program Files (x86)Growl for Windowsgrowlnotify.exe' /a:Lync /ai:$icon /r:$types "Registration."
#We just need the Model API for this example
import-module "C:Program Files (x86)Microsoft LyncSDKAssembliesDesktopMicrosoft.Lync.Model.Dll"
#Get a reference to the Client object
$client = [Microsoft.Lync.Model.LyncClient]::GetClient()
#Set the client to reference to the local client
$self = $client.Self
# What do we do here?
$conversationMgr = $client.ConversationManager
# Register events for existing conversations.
$i = 0
for ($i=0; $i -lt $conversationMgr.Conversations.Count; $i++) {
Register-ObjectEvent -InputObject $conversationMgr.Conversations[$i].Modalities[1] -EventName "InstantMessageReceived" `
                    -SourceIdentifier "new im $i" `
                    -action {
                               $message = $EventArgs.Text
                               Write-Host "DEBUG: New incoming IM - $message"
                               # Try to get the name of the person...
                               $contactInfo = $Event.Sender.Conversation.Participants[1].Contact.GetContactInformation([Microsoft.Lync.Model.ContactInformationType[]] @("FirstName", "LastName", "DisplayName", "PrimaryEmailAddress", "Photo", "IconUrl", "IconStream"))
                               $name = " "
                               if ($contactInfo.Get_Item("FirstName")) { $name = $contactInfo.Get_Item("FirstName") + " " + $contactInfo.Get_Item("LastName") + ":" }
                               elseif ($contactInfo.Get_Item("DisplayName")) { $name = $contactInfo.Get_Item("DisplayName") + ":"}
                               else { $name = $contactInfo.Get_Item("PrimaryEmailAddress") + ":" }
                               # We need to check if the Lync window (conversation?) has focus or not.
                               if (1) {
                                  # We need to send our growl notification.
                                  & 'C:Program Files (x86)Growl for Windowsgrowlnotify.exe' /a:Lync /n:new-im /t:"New Instant Message" "$name $message" 
                               }
                            }
}
# If this exits, no more events.
while (1) { }

每次我给别人输入即时消息时，它就像我试图处理传入消息一样。但没有什么东西会对他们开火，只是外向。我看了所有的文档，没有其他的候选事件，我确定是这个。但是Modality对象只是存储了一些关于它是IM还是屏幕共享之类的东西，没有什么有用的。

http://msdn.microsoft.com/en-us/library/lync/microsoft.lync.model.conversation.instantmessagemodality_di_3_uc_ocs14mreflyncclnt_members (v = office.14) . aspx

我哪里搞砸了?我更喜欢Powershell的答案，但我不认为这是Powershell特有的问题，所以如果你知道如何用c#或Visual Basic或类似的东西来解决，我也很感激。

Answer 1

我没有Lync，所以我可以自己测试，但是看看这个链接，它展示了如何使用API。

问题是(据我所知)每个参与者每个媒体都有一个模式。因此，对于仅使用文本的两个成员的对话，将有2种模式，一种用于传入消息(来自远程参与者)，另一种用于传出消息。这在

中指定

在接收、或发送即时消息时发生，如果InstantMessageModality属于本地参与者。

来源:MSDN

当你注册你的对象事件时，你将它注册到"你的模态"，而不是远程模态。要解决这个问题，您似乎需要从经理那里获取每个对话，查看每个参与者，除了代表您的参与者(检查IsSelf属性)。然后从参与者(除了你自己)那里获得模态，并注册InstantMessageReceived活动。

至少这是我从中得到的，但正如我所说，我没有使用Lync的经验，所以我很容易出错。

我对如何做到这一点的猜测(非常未经测试):

# What do we do here?  You get the manager the keeps track of every conversation
$conversationMgr = $client.ConversationManager
# Register events for existing conversations.
#You may need to use '$conversation in $conversationMgr.GetEnumerator()'
foreach ($conversation in $conversationMgr) {
    #Get remote participants
    $conversation.Participants | where { !$_.IsSelf } | foreach {
        #Get IM modality
        $textmod = [InstantMessageModality]($_.Modalities[ModalityTypes.InstantMessage])
        Register-ObjectEvent -InputObject $textmod -EventName "InstantMessageReceived" `
                    -SourceIdentifier "new im $i" `
                    -action {
                            #...
        }
    }
}