在数组中查找常用单词

Question

我有一个字符串：

Fragrances, Beauty & Health (153)
    Skin Care (146)
    Make Up (10)
    Health Care & Instruments (1)
    Hair Care (1)

我正在把它转换成一个数组：

$formatted = array_map('trim', preg_split("/[()]+/", $string, -1, PREG_SPLIT_NO_EMPTY));

结果：

Array
(
    [0] => Fragrances, Beauty & Health
    [1] => 153
    [2] => Skin Care
    [3] => 146
    [4] => Make Up
    [5] => 10
    [6] => Health Care & Instruments
    [7] => 1
    [8] => Hair Care
    [9] => 1
)

我应该怎么做才能达到想要的结果：

Array
(
    [Fragrances, Beauty & Health] => 153
    [Skin Care] => 146
    [Make Up] => 10
    [Health Care & Instruments] => 1
    [Hair Care] => 1
)

Answer 1

这应该适用于您：

首先，每行只explode()您的字符串，然后用array_map()遍历每个元素，并用(或)将其拆分。

之后，您可以简单地使用array_column()将第一列用作键，将第二列用作值。

<?php
    $arr = array_column(array_map(function($v){
        return array_map("trim", preg_split("/[()]+/", $v, -1, PREG_SPLIT_NO_EMPTY));
    }, explode(PHP_EOL, $str)), 1, 0);
    print_r($arr);
?>

输出：

Array
(
    [Fragrances, Beauty & Health] => 153
    [Skin Care] => 146
    [Make Up] => 10
    [Health Care & Instruments] => 1
    [Hair Care] => 1
)

编辑：

你不能有重复的密钥，所以如果你想保留价值最高的密钥，你可以这样做：

$arr = array_map(function($v){
    $arr = array_map("trim", preg_split("/[()]+/", $v, -1, PREG_SPLIT_NO_EMPTY));
    if(!isset($arr[1]))
        $arr[1] = 0;
    return $arr;
}, explode(PHP_EOL, $str));
usort($arr, function($a, $b){
    return $a[1] - $b[1];
});
$arr = array_column($arr, 1, 0);
print_r($arr);

Answer 2

$arr = explode("n",$array);
$desireArray = array();
foreach($arr as $value)
{
    $val = explode("(",$value);
    $desireArray[trim($val[0])] = trim($val[1],")");
}
print_R($desireArray);