编辑:现在这是我真正的问题。这是我的消息来源,但我的问题有点不同。如果数组键相同,则求和值。我的数组是:
Array
(
[one] => Array
(
[gozhi] => 2
[uzorong] => 1
[ngangla] => 4
[langthel] => 5
)
[two] => Array
(
[gozhi] => 5
[uzorong] => 0
[ngangla] => 3
[langthel] => 2
)
[three] => Array
(
[gozhi] => 3
[uzorong] => 0
[ngangla] => 1
[langthel] => 3
)
)
在上面的链接中,期望的结果是
Array
(
[gozhi] => 10
[uzorong] => 1
[ngangla] => 8
[langthel] => 10
)
但是我想要的结果是
Array
(
[one] => 12
[two] => 10
[three] => 7
)
<?php
$a = array(
array
(
'gozhi' => 2,
'uzorong' => 1,
'ngangla' => 4,
'langthel' => 5
)
,array
(
'gozhi' => 5,
'uzorong' => 0,
'ngangla' => 3,
'langthel' => 2
)
,array
(
'gozhi' => 3,
'uzorong' => 0,
'ngangla' => 1,
'langthel' => 3
)
);
$sum_arr = array();
foreach($a as $b)
{
if(is_array($b))
{
$sum = 0;
foreach($b as $key=>$value)
{
$sum += $value;
}
$sum_arr[] = $sum;
}
}
echo '<pre>';
print_r($sum_arr);
echo '</pre>';
?>
Output :
Array
(
[0] => 12
[1] => 10
[2] => 7
)
试试这个…
$sumArray = array();
foreach ($data as $key => $subArray) {
$sumArray[$key]=array_sum(array_values($subArray));
}
print_r($sumArray);
数组([1] => 12[二]=> 10[三]=> 7)
你所需要的只是一个嵌套的循环…
$sumArray = array();
foreach ($outerArray as $innerArray)
{
$sum = 0;
foreach ($innerArray as $key => $value)
{
$sum += $value;
}
$sumArray[] = $sum;
}
print_r($sumArray);