input_list = input("Enter numbers separated by spaces: ")
number = input_list.split()
for n in number:
a = int(n)
if len(number)!=5 or number>5 or number<0 :
print ('invalid input')
if 0< a <=5:
print ('x'* a)
elif a == 0:
print ('.')
我的程序正在检查输入的 5 位数字,就好像它们是一个数字一样,但我希望我的程序首先确保输入 5 位数字,然后检查它们是否在 0 到 5 之间,但程序将所有 5 位数字合并为一个数字,我希望程序自行检查列表的每个元素,在打印任何内容之前,我希望程序检查是否输入的数字满足所有条件,如果不打印(输入无效(并停止其
input_list = input("Enter numbers separated by spaces: ")
numbers = input_list.split()
if len(numbers) == 5 and all(0 <= int(n) <= 5 for n in numbers):
print("ok")
print("".join(numbers))
else:
print("invalid")
我在python 2中使用raw_input。
input_list = raw_input("Enter numbers separated by spaces: ").split()
numbers = [int(n) for n in input_list if 0 <= int(n) <= 5]
if len(numbers) != 5:
print ('invalid input')
for a in numbers:
if a == 0:
print ('.')
else:
print ('x'* a)
input_list = input("Enter numbers separated by spaces: ")
number = input_list.split()
if len(number) == 5:
for n in number:
a = int(n)
if 0< a <=5:
print ('x'* a)
elif a == 0:
print ('.')
else:
print ("Number does not lie in the range 0 to 5.")
else:
print ("Invalid Input.")
Yes, the above works but is should check input first to make sure it is valid
number = raw_input("Enter numbers separated by spaces: ")
2 num_list = number.split()
3 for n in num_list:
4 a = 'True'
5 if int(n) <0 or int(n) >5:
6 a = 'False'
7 break
8 if (len(num_list) == 5) and a == 'True':
9 for n in num_list:
10 b = int(n)
11 if 0< b <=5:
12 print ('x'* b)
13 elif b == 0:
14 print ('.')
15 else:
16 print 'Invalid Input!'