从文本文件中打印范围模式中的行

I Have file log.txt：

======================
Tue Jun 25 00:02:00 WIT 2013
======================

pool
    INFO     name               work
    INFO     threads.total      30
    INFO     threads.active     7
    INFO     threads.waiting    23
    INFO     jobs.queue.latency 0
    INFO     jobs.run.latency   139
    INFO     jobs.queue.tps     3
    INFO     jobs.start.tps     3
    INFO     jobs.finish.tps    3
    NORMAL   jobs.count         0
pool
    INFO     name               recv
    INFO     threads.total      40
    INFO     threads.active     27
    INFO     threads.waiting    13
    INFO     jobs.queue.latency 0
    INFO     jobs.run.latency   0
    INFO     jobs.queue.tps     0
    INFO     jobs.start.tps     0
    INFO     jobs.finish.tps    0
    NORMAL   jobs.count         0
pool
    INFO     name               send
    INFO     threads.total      10
    INFO     threads.active     0
    INFO     threads.waiting    10
    INFO     jobs.queue.latency 0
    INFO     jobs.run.latency   1
    INFO     jobs.queue.tps     5
    INFO     jobs.start.tps     5
    INFO     jobs.finish.tps    5
    NORMAL   jobs.count         0

======================
Tue Jun 25 00:03:00 WIT 2013
======================
pool
    INFO     name               work
    INFO     threads.total      30
    INFO     threads.active     15
    INFO     threads.waiting    15
    INFO     jobs.queue.latency 0
    INFO     jobs.run.latency   13
    INFO     jobs.queue.tps     1
    INFO     jobs.start.tps     0
    INFO     jobs.finish.tps    0
    NORMAL   jobs.count         46
    INFO     jobs.1.type        request
pool
    INFO     name               recv
    INFO     threads.total      40
    INFO     threads.active     27
    INFO     threads.waiting    13
    INFO     jobs.queue.latency 0
    INFO     jobs.run.latency   0
    INFO     jobs.queue.tps     0
    INFO     jobs.start.tps     0
    INFO     jobs.finish.tps    0
    NORMAL   jobs.count         0
pool
    INFO     name               send
    INFO     threads.total      10
    INFO     threads.active     0
    INFO     threads.waiting    10
    INFO     jobs.queue.latency 0
    INFO     jobs.run.latency   0
    INFO     jobs.queue.tps     0
    INFO     jobs.start.tps     0
    INFO     jobs.finish.tps    0
    NORMAL   jobs.count         0

我想要这样的结果：

======================
Tue Jun 25 00:03:00 WIT 2013
======================
    INFO     name               work
    NORMAL   jobs.count         46
    INFO     jobs.1.type        request

我已经使用：

cat log.txt |grep -B14 -A1 -i 'jobs.count         [1-9]{2,}' |
egrep -i "jobs.1.type|=|WIT|jobs.count         [1-9]"

如果名称不是"work"而是"send"或"recv"，那么"grep-B14"将无法获得日期。还有其他解决方案吗？另一方面，如果"jobs.count"不是"0"，我希望grep比get date="Tue Jun 25 00:03:00 WIT 2013"，get name="INFO name work"和get jobs type"INFO jobs.type request"：

GNU awk代码：

/WIT|INFO +name|jobs.1.type|jobs.count +[1-9]/{
if ($0 ~ /WIT/)
    {cheader=$0}
if ($0 ~ /INFO +name/)
    {cname=$0}
if ($0 ~ /jobs.count +[1-9]/)
    {ccount=$0}
if ($0 ~ /jobs.1.type/)
    {
    i++
    header[i]=cheader
    name[i]=cname
    count[i]=ccount
    type[i]=$0
    }
}
END {
    line="======================"
    for (a=1 ;a<=i ;a++)
    {
    if (count[a] != "")
        {
        print line
        print header[a]
        print line
        print name[a]
        print count[a]
        print type[a]
        }
    }
}

输出示例：

$awk-f c.awk文件======================2013年6月25日星期二00:03:00======================INFO名称工作正常工作计数46INFO jobs.1类型请求

awk '/WIT/ {date=$0} /name/ {printf "n%sn%sn", date, $0} /count|type/' file | 
awk -v RS="" '{for (i=1; i<=NF; i++) if ($i~/count/ && $(i+1)>0) {print; break}}'

Tue Jun 25 00:03:00 WIT 2013
    INFO     name               work
    NORMAL   jobs.count         46
    INFO     jobs.1.type        request

第一个awk打印包含日期和所需字段的段落
第二个awk读取段落，只打印计数>0的段落。

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