JavaScript中是否有等价的C#String.Format()

Question

C#具有非常强大的String.Format()，可以用参数替换{0}等元素。JavaScript有对等的吗？

Answer 1

尝试javascript的sprintf（）。

或

// First, checks if it isn't implemented yet.
if (!String.prototype.format) {
  String.prototype.format = function() {
    var args = arguments;
    return this.replace(/{(d+)}/g, function(match, number) { 
      return typeof args[number] != 'undefined'
        ? args[number]
        : match
      ;
    });
  };
}
"{0} is dead, but {1} is alive! {0} {2}".format("ASP", "ASP.NET")

两个答案都是从JavaScript中提取的，相当于printf/string.format

Answer 2

我正在使用：

String.prototype.format = function() {
    var s = this,
        i = arguments.length;
    while (i--) {
        s = s.replace(new RegExp('\{' + i + '\}', 'gm'), arguments[i]);
    }
    return s;
};

用法："Hello {0}".format("World");

我在JQuery 中的String.format中找到了它

更新：

在ES6/ES2015中，您可以使用字符串模板，例如

'use strict';
let firstName = 'John',
    lastName = 'Smith';
console.log(`Full Name is ${firstName} ${lastName}`); 
// or
console.log(`Full Name is ${firstName + ' ' + lastName}');

Answer 3

基于@Vlad Bezden的回答，我使用了这个稍微修改过的代码，因为我更喜欢命名占位符：

String.prototype.format = function(placeholders) {
    var s = this;
    for(var propertyName in placeholders) {
        var re = new RegExp('{' + propertyName + '}', 'gm');
        s = s.replace(re, placeholders[propertyName]);
    }    
    return s;
};

用法：

"{greeting} {who}!".format({greeting: "Hello", who: "world"})

String.prototype.format = function(placeholders) {
    var s = this;
    for(var propertyName in placeholders) {
        var re = new RegExp('{' + propertyName + '}', 'gm');
        s = s.replace(re, placeholders[propertyName]);
    }    
    return s;
};
$("#result").text("{greeting} {who}!".format({greeting: "Hello", who: "world"}));

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="result"></div>

Answer 4

我很久以前创建了它，相关问题

String.Format = function (b) {
    var a = arguments;
    return b.replace(/({{d}}|{d})/g, function (b) {
        if (b.substring(0, 2) == "{{") return b;
        var c = parseInt(b.match(/d/)[0]);
        return a[c + 1]
    })
};