我刚刚尝试了GCC 4.8令人兴奋的新功能AddressSanitizer。
该计划
#include <iostream>
int main(int argc, const char * argv[], const char * envp[]) {
int *x = nullptr;
int y = *x;
std::cout << y << std::endl;
return 0;
}
编译查找使用
g++-4.8 -std=gnu++0x -g -fsanitize=address -fno-omit-frame-pointer -Wall ~/h.cpp -o h
但是当我运行程序时,我得到
ASAN:SIGSEGV
=================================================================
==7531== ERROR: AddressSanitizer crashed on unknown address 0x000000000000 (pc 0x000000400aac sp 0x7fff11ce0fd0 bp 0x7fff11ce1000 T0)
AddressSanitizer can not provide additional info.
#0 0x400aab (/home/per/h+0x400aab)
#1 0x7fc432e1b76c (/lib/x86_64-linux-gnu/libc-2.15.so+0x2176c)
Stats: 0M malloced (0M for red zones) by 0 calls
Stats: 0M realloced by 0 calls
Stats: 0M freed by 0 calls
Stats: 0M really freed by 0 calls
Stats: 0M (0 full pages) mmaped in 0 calls
mmaps by size class:
mallocs by size class:
frees by size class:
rfrees by size class:
Stats: malloc large: 0 small slow: 0
这似乎是报告内存错误的不正确方法。我是否错过了一些编译或链接标志?
这是报告 NULL 取消引用的预期方法。您可以通过asan_symbolize.py(应该存在于 GCC 树中)运行程序输出,以获取源文件中的符号名称和行号。
我在 gcc 4.8 或 4.9 上找不到任何asan_symbolize.py。我在 https://code.google.com/p/address-sanitizer/issues/detail?id=223 中添加了一个解决方法