无法为我的 iOS VoIP 应用程序显示即将到来的呼叫视图控制器

Question

我希望我的应用程序在应用程序收到一些来电时显示传入呼叫视图控制器。

这是我用来显示来电的代码。从我的联系人视图控制器，这是来电发生时的活动视图。

- (void)showIncomigCallVC{
    [self performSegueWithIdentifier:@"segueToIncomingCallVC" sender:nil];
}

这是我的代码，由库调用。

    /* Callback called by the library upon receiving incoming call */
static void on_incoming_call(pjsua_acc_id acc_id, pjsua_call_id call_id,
                         pjsip_rx_data *rdata)
{
    pjsua_call_info ci;
    PJ_UNUSED_ARG(acc_id);
    PJ_UNUSED_ARG(rdata);
    pjsua_call_get_info(call_id, &ci);

    PJ_LOG(3,(THIS_FILE, "....nnn Incoming call from %.*s!!  nnn",
          (int)ci.remote_info.slen,
          ci.remote_info.ptr));
    ContactsViewController *incomingCallVC = [[ContactsViewController alloc]init];
    [incomingCallVC showIncomigCallVC];
    /* Automatically answer incoming calls with 200/OK */
    pjsua_call_answer(call_id, 200, NULL, NULL);
}

这是我的控制台输出：

20:39:37.482      XCPjsua.c  ......

Incoming call from <sip:[e-mail]>!!  

2017-01-16 20:39:37.494 simpleVoIP[922:19652] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Receiver (<ContactsViewController: 0x7bea3d00>) has  no segue with identifier 'segueToIncomingCallVC''
*** First throw call stack:
(
    0   CoreFoundation                      0x03a14212 __exceptionPreprocess + 194
    1   libobjc.A.dylib                     0x034d3e66 objc_exception_throw + 52
    2   UIKit                               0x01a69893 -[UIViewController shouldPerformSegueWithIdentifier:sender:] + 0
    3   simpleVoIP                          0x00089ba6 -[ContactsViewController showIncomigCallVC] + 70
    4   simpleVoIP                          0x00086caf on_incoming_call + 255
    5   simpleVoIP                          0x000fc273 pjsua_call_on_incoming + 3811
    6   simpleVoIP                          0x00103294 mod_pjsua_on_rx_request + 84
    7   simpleVoIP                          0x0012938f pjsip_endpt_process_rx_data + 351
    8   simpleVoIP                          0x00128bf2 endpt_on_rx_msg + 546
    9   simpleVoIP                          0x0012fba1 pjsip_tpmgr_receive_packet + 849
    10  simpleVoIP                          0x001315ec udp_on_read_complete + 316
    11  simpleVoIP                          0x0014b8e0 ioqueue_dispatch_read_event + 704
    12  simpleVoIP                          0x0014d5b2 pj_ioqueue_poll + 946
    13  simpleVoIP                          0x001290c3 pjsip_endpt_handle_events2 + 163
    14  simpleVoIP                          0x00102023 worker_thread + 99
    15  simpleVoIP                          0x0014eb96 thread_main + 86
    16  libsystem_pthread.dylib             0x04c8a11b _pthread_body + 184
    17  libsystem_pthread.dylib             0x04c8a063 _pthread_body + 0
    18  libsystem_pthread.dylib             0x04c8993e thread_start + 34
)
libc++abi.dylib: terminating with uncaught exception of type NSException

我是初学者，任何建议将不胜感激。提前致谢

Answer 1

您遇到崩溃，因为您正在以编程方式分配ContactsViewController，而不是从storyboard使用。

执行此操作时：

 ContactsViewController *incomingCallVC = [[ContactsViewController alloc]init];
 [incomingCallVC showIncomigCallVC];

您正在创建一个ContactsViewController实例，与我们storyboard中创建的实例无关。
可以克服这一点，但是，您正在尝试对viewController进行segue调用，仅加载到内存中但根本不可见的内容。那永远不会奏效，它总是会崩溃。

我建议立即展示您的viewController，无论 segue 背后的内容是什么，而不是创建一个viewController并用 segue 显示它。

编辑：

使用下面的代码，您应该能够从回调函数的末尾显示所需的UIViewController子类。

// Lets get keywindow 
UIWindow* keyWindow = [[[UIApplication sharedApplication] delegate] window]; 
keyWindow.frame = [UIScreen mainScreen].bounds; 
// Lets get `IncomingCallViewController` from storyboard 
UIStoryboard *sb = [UIStoryboard storyboardWithName:@"TheNameOfYourStoryboard" bundle:nil]; 
// do not forget to set the identifier of your viewController on the storyboard as "IncomingCallViewController" 
UIViewController *vc = [sb instantiateViewControllerWithIdentifier:@"IncomingCallViewController"]; 
// Lets present the keyWindow from the main thread
dispatch_async(dispatch_get_main_queue(), ^{ 
   keyWindow.rootViewController = vc; 
   [keyWindow makeKeyAndVisible]; 
});