在 c# 中使用子元素反序列化 xml 文件

Question

我正在尝试反序列化这种类型的 xml 文件

<?xml version="1.0" encoding="UTF-8"?>
<Network>
 <ROUTES>
  <ROUTE ID="RT_BALA_GLNC_R_162_154_1" DIRECTION="LEFT" ZONE="Richmond_Hill">
     <ENTRANCESIGNAL>BALA_GLNC_G162</ENTRANCESIGNAL>
     <EXITSIGNAL>BALA_DONS_G154</EXITSIGNAL>
     <POINTENDIDS>
        <POINTENDID POS="N">PT_BALA_GLNC_W11.TrackPortionConnection</POINTENDID>
        <POINTENDID POS="N">PT_BALA_GLNC_W23.TrackPortionConnection</POINTENDID>
     </POINTENDIDS>
  </ROUTE>
  <ROUTE ID="RT_BALA_ORLS_R_111_119_1" DIRECTION="RIGHT" ZONE="Richmond_Hill">
     <ENTRANCESIGNAL>BALA_ORLS_G111</ENTRANCESIGNAL>
     <EXITSIGNAL>BALA_ORLN_G119</EXITSIGNAL>
     <POINTENDIDS>
        <POINTENDID POS="N">PT_BALA_ORLS_W1.TrackPortionConnection</POINTENDID>
     </POINTENDIDS>
  </ROUTE>
  <ROUTE ID="RT_BALA_GLNC_R_162D_154_1" DIRECTION="LEFT" ZONE="Richmond_Hill">
     <ENTRANCESIGNAL>BALA_GLNC_G162D</ENTRANCESIGNAL>
     <EXITSIGNAL>BALA_DONS_G154</EXITSIGNAL>
     <POINTENDIDS>
        <POINTENDID POS="R">PT_BALA_GLNC_W11.TrackPortionConnection</POINTENDID>
        <POINTENDID POS="N">PT_BALA_GLNC_W23.TrackPortionConnection</POINTENDID>
     </POINTENDIDS>
  </ROUTE>
 </ROUTES>
</Network>

我试过这个

class Program
{
    static void Main(string[] args)
    {
        XmlSerializer deserializer = new XmlSerializer(typeof(Network));
        TextReader reader = new StreamReader(@"xml File Location");
        object obj = deserializer.Deserialize(reader);
        Network XmlData = (Network)obj;
        reader.Close();
        Console.ReadLine();
    }
}
[XmlRoot("Network")]
public class Network
{
    [XmlElement("ROUTES")]
    public List<ROUTE> ROUTES { get; set; }
}
public class ROUTE
{
    [XmlAttribute("ID")]
    public string ID { get; set; }
    [XmlAttribute("DIRECTION")]
    public string DIRECTION { get; set; }
    [XmlElement("ENTRANCESIGNAL")]
    public string ENTRANCESIGNAL { get; set; }
    [XmlElement("EXITSIGNAL")]
    public string EXITSIGNAL { get; set; }
    [XmlElement("POINTENDIDS")]
    public POINTENDIDS POINTENDIDS { get; set; }
}
public class POINTENDIDS
{
    [XmlElement("POINTENDID")]
    public List<POINTENDID> POINTENDID { get; set; }
}
public class POINTENDID
{
    [XmlAttribute("POS")]
    public string POS { get; set; }
}

我正在控制台应用程序中执行此操作，

我开始调试并将断点放在网络上 XmlData = （网络）obj;

我只有 1 条路线和"ID"、"方向"、"入口信号"的值......等设置为空

作为C#编程的初学者，我真的不明白我该怎么办！

需要有关此实施的帮助

Answer 1

修复网络类。 方括号中的名称区分大小写。 您还需要添加 Xml 数组属性。

    [XmlRoot("Network")]
    public class Network
    {
        [XmlArrayItem("ROUTE")]
        [XmlArray("ROUTES")]
        public List<ROUTE> ROUTES { get; set; }
    }

Answer 2

using System.Xml; //XmlDoc
using System.Xml.Linq;//XElement
using System.IO;//Path,File,Directory, Stream

读取和解析 xml 文件：

XmlDocument XmlDoc = new XmlDocument();
XmlDoc.Load(XmlFilePath);

另一种方法是改用XElement：

XElement a = XElement.Load(@"c:pathfile");

大多数情况下，我更喜欢XElement而不是XmlDocument，但这是个人的。

如果你从 C# 开始，你需要一本书和一个更简单的项目。流和 XML 在语法上很复杂。此外，控制台应用程序很丑陋，而Forms应用程序使用VisualStudio的图形工具并不难做到。

Answer 3

C# 类与 XML 文件不完全对齐，序列化程序仅返回部分结果。此处概述了如果 XML 结构是固定的，您可以执行哪些操作。

https://stackoverflow.com/a/17315863/99804

然后，这将按您的要求工作。

您将获得以下自动生成的代码。注意：我已经清理了输出以使用自动属性等。

using System;
using System.Xml.Serialization;
// NOTE: Generated code may require at least .NET Framework 4.5 or .NET Core/Standard 2.0.
/// <remarks />
[Serializable]
[XmlType(AnonymousType = true)]
[XmlRoot(Namespace = "", IsNullable = false)]
public class Network
{
    /// <remarks />
    [XmlArrayItem("ROUTE", IsNullable = false)]
    public NetworkROUTE[] ROUTES { get; set; }
}
[Serializable]
[XmlType(AnonymousType = true)]
public class NetworkROUTE
{
    [XmlAttribute]
    public string DIRECTION { get; set; }
    public string ENTRANCESIGNAL { get; set; }
    public string EXITSIGNAL { get; set; }
    [XmlAttribute]
    public string ID { get; set; }
    [XmlArrayItem("POINTENDID", IsNullable = false)]
    public NetworkROUTEPOINTENDID[] POINTENDIDS { get; set; }
    [XmlAttribute]
    public string ZONE { get; set; }
}
[Serializable]
[XmlType(AnonymousType = true)]
public class NetworkROUTEPOINTENDID
{
    [XmlAttribute]
    public string POS { get; set; }
    [XmlText]
    public string Value { get; set; }
}