我想在我的可折叠d3布局中,基于最底层正上方的一个节点为路径着色。显然,只有当子节点正上方的多个节点展开时,才会有不同的颜色。
我使用的是d3js示例中的代码,只做了一些小的修改:
function buildTree(data) {
var margin = {top: 20, right: 120, bottom: 20, left: 120},
width = 960 - margin.right - margin.left,
height = 800 - margin.top - margin.bottom;
var i = 0,
duration = 750,
root;
var tree = d3.layout.tree()
.size([height, width]);
var diagonal = d3.svg.diagonal()
.projection(function (d) {
return [d.y, d.x];
});
var svg = d3.select("#node").append("svg")
.attr("width", width + margin.right + margin.left)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
root = data;
root.x0 = height / 2;
root.y0 = 0;
function collapse(d) {
if (d.children) {
d._children = d.children;
d._children.forEach(collapse);
d.children = null;
}
}
root.children.forEach(collapse);
update(root);
d3.select(self.frameElement).style("height", "800px");
function update(source) {
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse(),
links = tree.links(nodes);
// Normalize for fixed-depth.
nodes.forEach(function (d) {
d.y = d.depth * 180;
});
// Update the nodes…
var node = svg.selectAll("g.node")
.data(nodes, function (d) {
return d.id || (d.id = ++i);
});
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function (d) {
return "translate(" + source.y0 + "," + source.x0 + ")";
})
.on("click", click);
nodeEnter.append("circle")
.attr("r", 1e-6)
.style("fill", function (d) {
return d._children ? "lightsteelblue" : "#fff";
});
nodeEnter.append("text")
.attr("x", function (d) {
return d.children || d._children ? -10 : 10;
})
.attr("dy", "1em")
.attr("text-anchor", function (d) {
return d.children || d._children ? "end" : "start";
})
.text(function (d) {
return d.name;
})
.style("fill-opacity", 1e-6);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function (d) {
return "translate(" + d.y + "," + d.x + ")";
});
nodeUpdate.select("circle")
.attr("r", 4.5)
.style("fill", function (d) {
return d._children ? "lightsteelblue" : "#fff";
});
nodeUpdate.select("text")
.style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function (d) {
return "translate(" + source.y + "," + source.x + ")";
})
.remove();
nodeExit.select("circle")
.attr("r", 1e-4);
nodeExit.select("text")
.style("fill-opacity", 1e-6);
// Update the links…
var link = svg.selectAll("path.link")
.data(links, function (d) {
return d.target.id;
});
// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function (d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
});
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function (d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function (d) {
d.x0 = d.x;
d.y0 = d.y;
});
}
// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(d);
}
}
"链接"颜色(这是我想要改变的)来自一些定义的样式:
.node {
cursor: pointer;
}
.node circle {
fill: #fff;
stroke: steelblue;
stroke-width: 2px;
}
.node text {
font: 12px sans-serif;
fill: white;
}
.link {
fill: none;
stroke: white;
stroke-width: 1.5px;
}
我在黑色背景上,所以我想把颜色保持为红色、绿色、蓝色、白色等(那些可以在黑色背景下看到的颜色)。
您可以通过在代码中设置笔划颜色来动态地为链接着色。节点的深度(如果我理解正确的话,就是你想要的)是它的数据的一部分,所以你可以直接引用它。
var color = d3.scale.category20();
// ...
link.transition()
.duration(duration)
.attr("d", diagonal)
.style("stroke", function(d) { return color(d.source.depth); });
您可以在创建link
颜色时设置它们,代码如下:
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function (d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
})
.attr("stroke", function (d) { return 'blue'; })
// ^^ return your color here.
然后可以安全地删除.link
的stroke
的CSS定义。