Java Spring链接一对一关系

Question

希望我能得到一些解决特定问题的帮助。我基本上是在尝试创建一个REST API端点，该端点显示我的用户和AMP之间的一对一关系；USERPROFILE类。我正在尝试使用注释来执行此操作，但我没有任何运气。我似乎无法返回用户信息以及关联的个人资料信息。这是我的班级

package com.account.service.model;
import com.fasterxml.jackson.annotation.JsonBackReference;
import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonIgnore;
import javax.persistence.*;
import java.util.Date;
@Entity
@Table(name = "users")
public class User {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;
    private String email;
    private Boolean active;
    @JsonIgnore
    private String password;
    @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd")
    private Date created_at;
    @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd")
    private Date updated_at;
    @OneToOne(cascade = CascadeType.ALL, mappedBy = "user")
    @JoinColumn(name = "user_id")
    @JsonBackReference
    private UserProfile userProfile;
    public User(){}
    public User(String email, Boolean active, String password, Date created_at, Date updated_at) {
        this.email = email;
        this.active = active;
        this.password = password;
        this.created_at = created_at;
        this.updated_at = updated_at;
    }
    public Integer getId() {
        return id;
    }
    public void setId(Integer id) {
        this.id = id;
    }
    public String getEmail() {
        return email;
    }
    public void setEmail(String email) {
        this.email = email;
    }
    public Boolean getActive() {
        return active;
    }
    public void setActive(Boolean active) {
        this.active = active;
    }
    public String getPassword() {
        return password;
    }
    public void setPassword(String password) {
        this.password = password;
    }
    public Date getCreated_at() {
        return created_at;
    }
    public void setCreated_at(Date created_at) {
        this.created_at = created_at;
    }
    public Date getUpdated_at() {
        return updated_at;
    }
    public void setUpdated_at(Date updated_at) {
        this.updated_at = updated_at;
    }
    public UserProfile getUserProfile() {
        return userProfile;
    }
    public void setUserProfile(UserProfile userProfile) {
        this.userProfile = userProfile;
    }
}

这是用户配置文件

package com.account.service.model;
import com.fasterxml.jackson.annotation.JsonManagedReference;
import javax.persistence.*;
@Entity
@Table(name = "user_profiles")
public class UserProfile {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;
    private String first_name;
    private String last_name;
    @OneToOne(cascade = CascadeType.ALL, optional = false)
    @JsonManagedReference
    private User user;
    public UserProfile(){}
    public UserProfile(String first_name, String last_name, User user) {
        this.first_name = first_name;
        this.last_name = last_name;
        this.user = user;
    }
    public Integer getId() {
        return id;
    }
    public void setId(Integer id) {
        this.id = id;
    }
    public String getFirst_name() {
        return first_name;
    }
    public void setFirst_name(String first_name) {
        this.first_name = first_name;
    }
    public String getLast_name() {
        return last_name;
    }
    public void setLast_name(String last_name) {
        this.last_name = last_name;
    }
    public User getUser() {
        return user;
    }
    public void setUser(User user) {
        this.user = user;
    }
}

我得到的响应是缺少配置文件关联的以下内容。

[
    {
        "id": 1,
        "email": "[e-mail]",
        "active": true,
        "created_at": "2017-12-21",
        "updated_at": "2017-12-21"
    }
]

关于问题可能是什么的想法？

目的是显示以下内容：

[
    {
        "id": 1,
        "email": "[e-mail]",
        "active": true,
        "created_at": "2017-12-21",
        "updated_at": "2017-12-21",
        "profile": {
            "id": 1,
            "first_name": "master",
            "last_name": "splinter"
        }
    }
]

Answer 1

弄清楚了，如果其他任何人都陷入了此类问题上，请查看@JsonBackReference，这应该在您的用户类上使用，而不是在您的个人资料类中。