空手道:从JSON中删除一个动态元素

Question

* def res1 = {"member":{"muid":"MBR1"},"part":[{"PID":"M123"},{"supportedMembers":[{"muid":"MBR3","status":{"code":"A"}},{"muid":"MBR2","status":{"code":"I"}}]}]}
* def res2 = {"members":[{"member":{"muid":"MBR2","test":[{"EID":"E123"}]}},{"member":{"muid":"MBR3","test":[{"EID":"E123"}]}}]}

空手道：匹配两个不同JSON的数组元素我还有一个要求，与我之前的职位有关。

* def id = res1.member.muid

我想从res2响应中删除id，它可以是res2.members.member中的任何位置，并与res1进行匹配以查看muid的存在我试过下面这样的方法，但不起作用：

* karate.remove('$res2.members[*]..muid','$.muid[id]') 

Answer 1

示例代码：

Feature: Validation
Scenario:
* def res1 = {"member":{"muid":"MBR1"},"part":[{"PID":"M123"},{"supportedMembers":[{"muid":"MBR3","status":{"code":"A"}},{"muid":"MBR2","status":{"code":"I"}}]}]}
* def res2 = {"members":[{"member":{"muid":"MBR2","test":[{"EID":"E123"}]}},{"member":{"muid":"MBR3","test":[{"EID":"E123"}]}}]}
* def id = res1.member.muid
* def res2ids = $res2.members[*]..muid
* def data2 = karate.mapWithKey(res2ids, 'muid')
* print data2
* def res2ids = karate.jsonPath(data2, "$[?(@.muid != '" + id+ "')]")
* def res2ids = $res2ids[*]..muid
* print res2ids
* match res1.part[1].supportedMembers[*].muid contains only res2ids