如何简化具有相似元素的ng-switch

Question

我有以下代码:

<span ng-switch="status">
    <span ng-switch-when="NOT OK">
        <span style="color: red;" ng-bind="status"></span>
    </span>
    <span ng-switch-when="OK">
        <span style="color: green;" ng-bind="status"></span>
    </span>
    <span ng-switch-default>
        <span ng-bind="status"></span>
    </span>
 </span>

有任何方法来优化这个代码?我想我有一些ng绑定的重复

Answer 1

可以使用ng-class并在css规则中设置颜色

<span ng-bind="status" 
      ng-class="{'green-class': status=='OK', 'red-class': status=='NOT OK'}" ></span>

或者使用ng-style