获取表单的FormController

Question

在我的控制器中有这样的代码:

var forms = $('form'); // my selector is a bit more complex.
var form = forms[0];

这给了我这个表单。从这我怎么得到的FormController，以便我可以检查属性，如$质朴，$无效等?

var formController = // how to get this from form?
var ispristine = formController.$pristine;

我实际上有多个子窗体，我必须获得它们的原始状态。

谢谢

Answer 1

我认为你可以这样做来获得窗体的"FormController"属性:

    // Get hold of the form in your DOM
    var forms = $('form');
    var form = forms[0];
    // Get hold of the form's scope object, which is injected with an object containing these properties.
    // Note that 'formName is the name of the form element in html. (<form name='formName'>....</form>
    var formScope = $(form).scope().formName;
    var ispristine = formScope.$pristine;

注意，这只在表单元素有name属性时起作用!