我正在尝试创建一个一次性密码访问安卓应用程序。我已经使用 wamp 创建了一个本地主机服务器,我正在尝试使用我设计的移动应用程序访问该内容。不幸的是,我在我的日志猫中收到如下错误:
03-07 10:42:35.097 31217-31217/com.example.user.myapplication V/ActivityThread: updateVisibility : ActivityRecord{1ecab2fb token=android.os.BinderProxy@23c38b5b {com.example.user.myapplication/com.example.user.myapplication.activity.SmsActivity}} show : true
03-07 10:42:36.607 31217-31217/com.example.user.myapplication I/Timeline: Timeline: Activity_idle id: android.os.BinderProxy@23c38b5b time:52633449
03-07 10:42:37.397 31217-31217/com.example.user.myapplication D/ViewRootImpl: ViewPostImeInputStage ACTION_DOWN
03-07 10:42:37.537 31217-32544/com.example.user.myapplication E/SmsActivity: Posting params: {email=thomasbi@gmail.com, name=Thomas, mobile=9002378900}
03-07 10:42:37.537 31217-32544/com.example.user.myapplication I/System.out: (HTTPLog)-Static: isSBSettingEnabled false
03-07 10:42:37.537 31217-32544/com.example.user.myapplication I/System.out: KnoxVpnUidStorageknoxVpnSupported API value returned is false
03-07 10:42:37.547 31217-31217/com.example.user.myapplication E/SmsActivity: Error: java.net.SocketException: socket failed: EACCES (Permission denied)
03-07 10:42:37.617 31217-31217/com.example.user.myapplication D/SRIB_DCS: log_dcs ThreadedRenderer::initialize entered!
我已经包含了所有的权限,这是我的Android清单.xml文件
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.example.user.myapplication">
<application
android:name=".app.MyApplication"
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:supportsRtl="true"
android:theme="@style/MyMaterialTheme">
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.RECEIVE_SMS" />
<uses-permission android:name="android.permission.READ_SMS" />
<activity
android:name=".activity.SmsActivity"
android:label="@string/title_activity_sms">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity
android:name=".activity.MainActivity"
android:label="@string/app_name"
android:windowSoftInputMode="adjustResize">
</activity>
<!-- SMS Receiver -->
<receiver android:name=".receiver.SmsReceiver">
<intent-filter android:priority="99999">
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
<!-- Intent service -->
<service
android:name=".service.HttpService"
android:exported="false" />
</application>
这是我的权限.java文件,该文件是为在上述错误后提出请求而编写的:
import android.Manifest;
import android.app.Activity;
import android.content.Context;
import android.content.Intent;
import android.content.pm.PackageManager;
import android.os.Bundle;
import android.support.design.widget.Snackbar;
import android.support.v4.app.ActivityCompat;
import android.support.v4.content.ContextCompat;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.Toolbar;
import android.view.View;
import android.widget.Button;
import android.widget.Toast;
public class Permission extends AppCompatActivity implements View.OnClickListener{
private Context context;
private Activity activity;
private static final int PERMISSION_REQUEST_CODE = 1;
private View view;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.request_main);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
context = getApplicationContext();
activity = this;
Button check_permission = (Button)findViewById(R.id.check_permission);
Button request_permission = (Button)findViewById(R.id.request_permission);
check_permission.setOnClickListener(this);
request_permission.setOnClickListener(this);
}
@Override
public void onClick(View v) {
view = v;
int id = v.getId();
switch (id){
case R.id.check_permission:
if (checkPermission()) {
Snackbar.make(view,"Permission already granted.",Snackbar.LENGTH_LONG).show();
} else {
Snackbar.make(view,"Please request permission.",Snackbar.LENGTH_LONG).show();
}
break;
case R.id.request_permission:
if (!checkPermission()) {
requestPermission();
} else {
Snackbar.make(view,"Permission already granted.",Snackbar.LENGTH_LONG).show();
}
break;
}
}
private boolean checkPermission(){
int result = ContextCompat.checkSelfPermission(context, Manifest.permission.RECEIVE_SMS);
if (result == PackageManager.PERMISSION_GRANTED){
return true;
} else {
return false;
}
}
private void requestPermission(){
if (ActivityCompat.shouldShowRequestPermissionRationale(activity,Manifest.permission.RECEIVE_SMS)){
Toast.makeText(context,"SMS permission allows us to receive sms. Please allow in App Settings for additional functionality.",Toast.LENGTH_LONG).show();
} else {
ActivityCompat.requestPermissions(activity,new String[]{Manifest.permission.RECEIVE_SMS},PERMISSION_REQUEST_CODE);
}
}
@Override
public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults) {
switch (requestCode) {
case PERMISSION_REQUEST_CODE:
if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
Snackbar.make(view,"Permission Granted, Now you can access SMS.",Snackbar.LENGTH_LONG).show();
} else {
Snackbar.make(view,"Permission Denied, You cannot access SMS.",Snackbar.LENGTH_LONG).show();
}
break;
}
}}
当我运行以下代码时,我在日志猫和应用程序停止时没有收到错误,包安装程序已停止。我现在有点困惑,我知道我被一些愚蠢的东西困住了。如果有人能帮助我解决这个问题,我会很高兴。
基本上,您需要请求的唯一权限是SMS权限(Internet不是危险权限,您不必向用户请求)。Google建议您在使用权限之前请求权限,而不是一次全部请求(例如首次启动应用程序时)。谷歌还提供了有关如何最好地实施以及何时在其开发人员文档中提供的大量细节,这些很难在这里总结。请查看此处的开发人员文档,了解代码详细信息,以及 Material Design 文档,了解如何根据应用情况最好地实现。
如果您需要更多详细信息或有关权限的任何其他问题,请告诉我。