C-蒙蒂大厅游戏:如何打印计算机打开的门

Question

#include <stdio.h>
#include <time.h>
int main(void)
{
    static int games = 0;
    static int stayWins = 0;
    static int switchWins = 0;
    int chosenDoor;
    int remainingDoor;
    int revealedDoor;
    int winningDoor;
    int option;
    printf("Type 0 to stop choosing and print results:  ");
    srand (time(NULL));
    do
    {
    printf("Choose door 1, 2, or 3:  ");
    scanf("%d",&chosenDoor);
    if (chosenDoor==0)
        break;
    printf("Enter '1' for stay; Enter '2' for switch:");
    scanf("%d",&option);
    winningDoor = rand() % 3 + 1;
        do
        {
            revealedDoor = rand() % 3 + 1;
        } while (revealedDoor == chosenDoor || revealedDoor == winningDoor);
        do
        {
            remainingDoor = rand() % 3+1;
        } while (remainingDoor == chosenDoor || remainingDoor == revealedDoor);
        option = rand() % 2 + 1;
        if (option == 1)
        {
            if (chosenDoor == winningDoor)
            {
                printf("You win.n");
                stayWins++;
            }
            else
            {
                printf("You lose.n");
            }
        }
        if (option == 2)
        {
            chosenDoor = remainingDoor;
            if (chosenDoor == winningDoor)
            {
                printf("You win.n");
                switchWins++;
            }
            else
            {
                printf("You lose.n");
            }
        }
        games++;
    } while (chosenDoor!=0);
printf("Out of %d games, the contestant won %d times by staying with his/her original choice and won %d times by switching his/her choice.",games,stayWins,switchWins);
    return 0;
}

这是一个运行Monty Hall游戏的代码，用户在其中选择了三扇门中的一扇门。一扇门有奖品，另外两扇门是假的。用户选择门1、2或3，并在程序打开一个错误门之一时选择是否切换门。

我该如何使该程序打开门，这门必须是没有奖品的后面的门，而用户> and 打印其决定。

这是印刷的：

...
Choose door (1,2,3): 
Enter 1 for stay; 2 for switch: 
You win/lose.
...

这是我要打印的内容：

...
Choose door (1,2,3): 
Door X has been opened to reveal a false door.
Enter 1 for stay; 2 for switch: 
You win/lose.
...

感谢您的所有帮助。谢谢你，欢呼！

Answer 1

如果门是选择的门和/或奖品门，请选择一个随机门，然后递增或减小门号。

以1,2,3,1,2,3的1,2,3,1,2,3，...订购：

door = door%3 + 1;

减少：

door = (door + 1)%3 + 1;

...或只是增加两次。