如何检测用户何时连接到公共WiFi但未批准WiFi使用期限

Question

我的应用需要在具有免费公共WiFi网络的工作场所/机场上工作。

我想在用户需要通过网络浏览器批准WiFi使用期限时通知用户。

我尝试提取信息，但没有找到任何属性/信息来隔离此情况

public static void haveNetworkConnection(Context mContext) {
    ConnectivityManager cm = (ConnectivityManager) mContext.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();

    if (activeNetwork != null) { // connected to the internet
        if (activeNetwork.getType() == ConnectivityManager.TYPE_WIFI) {
            // connected to wifi
            Toast.makeText(mContext, activeNetwork.getTypeName(), Toast.LENGTH_SHORT).show();
            printWifiInformation(activeNetwork);
        } else if (activeNetwork.getType() == ConnectivityManager.TYPE_MOBILE) {
            // connected to the mobile provider's data plan
            Toast.makeText(mContext, activeNetwork.getTypeName(), Toast.LENGTH_SHORT).show();
        }
    } else {
        Toast.makeText(mContext, "Not connected", Toast.LENGTH_SHORT).show();
    }
}
public static void printWifiInformation(NetworkInfo activeNetwork){
    System.out.println("************************************************************************************");
    System.out.println("1 . describeContents         " + activeNetwork.describeContents());
    System.out.println("2 . getDetailedState         " + activeNetwork.getDetailedState());
    System.out.println("3 . getExtraInfo             " + activeNetwork.getExtraInfo());
    System.out.println("4 . getReason                " + activeNetwork.getReason());
    System.out.println("5 . getState                 " + activeNetwork.getState());
    System.out.println("6 . getSubtype               " + activeNetwork.getSubtype());
    System.out.println("7 . getSubtypeName           " + activeNetwork.getSubtypeName());
    System.out.println("8 . getSubtypeName           " + activeNetwork.getSubtypeName());
    System.out.println("9 . getType                  " + activeNetwork.getType());
    System.out.println("10. getTypeName              " + activeNetwork.getTypeName());
    System.out.println("11. isAvailable              " + activeNetwork.isAvailable());
    System.out.println("12. isConnected              " + activeNetwork.isConnected());
    System.out.println("13. isConnectedOrConnecting  " + activeNetwork.isConnectedOrConnecting());
    System.out.println("14. isFailover               " + activeNetwork.isFailover());
    System.out.println("15. isRoaming                " + activeNetwork.isRoaming());
    System.out.println("************************************************************************************");
}

单击Web浏览器之前和之后检查时，我得到了相同的结果。请指教，谢谢，路德

Answer 1

您应该从执行连接性检查开始以验证您在 captive Portal walled garden 。。

这里有一个很好的解释。

仍然，这并不能为您提供有关圈养门户本身的信息。

因此，您必须手动处理HttpUrlConnection响应标头并寻找重定向

HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
   try {
     InputStream in = new BufferedInputStream(urlConnection.getInputStream());
     if (!url.getHost().equals(urlConnection.getURL().getHost())) {
      // we were redirected! Kick the user out to the browser to sign on?
     }
     ...
   } finally {
     urlConnection.disconnect();
   }

官方文档足够慷慨，可以提供一系列示例，包括处理网络登录，HTTP身份验证以及处理cookie。你应该看看。希望这会有所帮助！