我当前正在将代码从sass转换为更少。
我对以下代码行有问题:
&[data-rating = "@{counter - 0.5}"] { // THIS DOES NOT WORK
我如何与变量一起工作并从我的计数器var中减去0.5,然后用一对引号将其放置在HTML数据属性中。
我包含了两个代码示例,因此您可以使用代码并运行它以查看我的结果。
sass:
.reviews-stars {
display: inline-block;
@for $i from 1 through 5 {
&[data-rating = "#{$i}"] {
.star:nth-child(-n + #{$i}):before {
color: green;
}
}
&[data-rating = "#{$i - 0.5}"] {
.star:nth-child(-n + #{$i}):before {
color: red;
}
}
}
}
少:
.looper-review-stars(@counter) when (@counter > 0) {
.looper-review-stars((@counter - 1)); // next iteration
&[data-rating = "@{counter}"] { // THIS WORKS
.star:nth-child(-n + @{counter}):before { // THIS WORKS
color: green;
}
}
// THIS DOES NOT WORK IT RETURNS THE STRING "@{counter - 0.5}"
&[data-rating = "@{counter - 0.5}"] { // THIS DOES NOT WORK
.star:nth-child(-n + @{counter}):before { // THIS WORKS
color: red;
}
}
}
.reviews-stars {
display: inline-block;
.looper-review-stars(5); // launch the loop
}
您可以使用以下摘要中的临时变量进行操作。由于选择器是字符串,我认为最好将所有数学操作远离它和单独的语句。
.looper-review-stars(@counter) when (@counter > 0) {
.looper-review-stars((@counter - 1)); // next iteration
&[data-rating = "@{counter}"] {
.star:nth-child(-n + @{counter}):before {
color: green;
}
}
@temp: @counter - .5; /* temporary variable */
&[data-rating = "@{temp}"] {
.star:nth-child(-n + @{counter}):before {
color: red;
}
}
}
.reviews-stars {
display: inline-block;
.looper-review-stars(5); // launch the loop
}