给定一个任意的monid文档,我如何将其转换为JSON并包含任何嵌入的结构,而不需要在我的to_json语句中特别包含这些结构。
例如:#!/usr/bin/env ruby
require 'mongoid'
require 'json'
require 'pp'
class Doc
include Mongoid::Document
include Mongoid::Timestamps
field :doc_specific_info , type: String
embeds_many :persons
end
class Person
include Mongoid::Document
field :role , type: String
field :full_name , type: String
embeds_many :addresses
embedded_in :Doc
end
class Address
include Mongoid::Document
field :full_address , type: String
end
doc = Doc.new
doc.doc_specific_info = "TestReport"
p = Person.new
p.role = 'buyer'
p.full_name = 'JOHN DOE'
doc.persons << p
a = Address.new
a.full_address = '1234 nowhere ville'
doc.persons.first.addresses << a
# THIS STATEMENT
pp JSON.parse(doc.to_json(:include => { :persons => { :include => :addresses } } ) )
# GIVES ME
# {"_id"=>"4ee0d30fab1b5c5743000001",
# "created_at"=>nil,
# "doc_specific_info"=>"TestReport",
# "updated_at"=>nil,
# "persons"=>
# [{"_id"=>"4ee0d30fab1b5c5743000002",
# "full_name"=>"JOHN DOE",
# "role"=>"buyer",
# "addresses"=>
# [{"_id"=>"4ee0d30fab1b5c5743000003",
# "full_address"=>"1234 nowhere ville"}]}]}
# THIS STATEMENT
pp JSON.parse(doc.to_json() )
# GIVES ME
# {"_id"=>"4ee0d2f8ab1b5c573f000001",
# "created_at"=>nil,
# "doc_specific_info"=>"TestReport",
# "updated_at"=>nil}
那么我想要的是一个像这样的语句:
# FOR A STATEMENT LIKE THIS
pp JSON.parse(doc.to_json( :everything } ) )
# TO GIVE ME THE COMPLETE DOCUMENT LIKE SO:
# {"_id"=>"4ee0d30fab1b5c5743000001",
# "created_at"=>nil,
# "doc_specific_info"=>"TestReport",
# "updated_at"=>nil,
# "persons"=>
# [{"_id"=>"4ee0d30fab1b5c5743000002",
# "full_name"=>"JOHN DOE",
# "role"=>"buyer",
# "addresses"=>
# [{"_id"=>"4ee0d30fab1b5c5743000003",
# "full_address"=>"1234 nowhere ville"}]}]}
这样的语句存在吗?如果不是,那么我唯一的选择是回避文档的结构并自己生成适当的include吗?如果有另一种方法可以将整个文档可视化,那会更好吗?
这个问题是由论坛上的垃圾回答的,但是他没有发布答案,所以我正在这样做。
答案是使用"doc.as_document。As_json ",它会给你整个文档。
pp doc.as_document.as_json
您可以在文档中覆盖#to_json方法来添加所有include。
class Person
def to_json(*args)
super(args.merge({:include => { :persons => { :include => :addresses } } } )
end
end
现在你可以拥有一切了
person.to_json()
如果你想只返回:everything
选项,你可以这样做:
class Person
def to_json(*args)
if args[0] == :everything
super(args.merge({:include => { :persons => { :include => :addresses } } } )
else
super(args)
end
end
end