通过xml循环,然后更新SQL中的xml变量



我的xml看起来像ff:

<root>
  <TemplateQuestion>
    <Row rfqID="1" rftID="1" questionDesc="Question 1" responseType="1" rfqDisplayOrder="1" deletedBit="0" />
    <Row rfqID="2" rftID="1" questionDesc="Question 2" responseType="2" rfqDisplayOrder="2" deletedBit="0" />
    <Row rfqID="3" rftID="1" questionDesc="Question 3" responseType="3" rfqDisplayOrder="3" deletedBit="0" />
  </TemplateQuestion>
</root>

现在我的目标是使rfqID前面有字母"q"

<root>
  <TemplateQuestion>
    <Row rfqID="q1" rftID="1" questionDesc="Question 1" responseType="1" rfqDisplayOrder="1" deletedBit="0" />
    <Row rfqID="q2" rftID="1" questionDesc="Question 2" responseType="2" rfqDisplayOrder="2" deletedBit="0" />
    <Row rfqID="q3" rftID="1" questionDesc="Question 3" responseType="3" rfqDisplayOrder="3" deletedBit="0" />
  </TemplateQuestion>
</root>

我正在通过这样做来实现这一点:

    declare @xml XML
    set @xml = (select dbo.udfGetXMLVal(1))
    declare @nodeCount int
    declare @i int
    declare @qid nvarchar(20)
    set @i = 1
    select @nodeCount = @xml.value('count(/root/TemplateQuestion/Row/@rfqID)','int')
    while(@i <= @nodeCount)
    begin
    select @qid = x.value('@rfqID[1]', 'VARCHAR(20)') 
    from @xml.nodes('/root/TemplateQuestion/Row[position()=sql:variable("@i")]') e(x)
    set @qid = 'q' + @qid
    select @qid
    Set @xml.modify('replace value of (/root/TemplateQuestion/Row/@rfqID)[1] with sql:variable("@qid")')
    set @i = @i + 1 
end

我的这条线路有问题:

Set @xml.modify('replace value of (/root/TemplateQuestion/Row/@rfqID)[1] with sql:variable("@qid")')

如何将[1]替换为变量@I?当我尝试使用sql:variable时,字符串文字会出现一些错误。

如果您能提供任何帮助,我们将不胜感激。感谢

"如何将[1]替换为变量@i?当我尝试使用sql:variable时,字符串文字出现一些错误"

您可以这样做(在SQLServer2008R2中测试并工作):

Set @xml.modify('
    replace value of ((/root/TemplateQuestion/Row/@rfqID)[sql:variable("@i")] )[1]
    with sql:variable("@qid")
')

快速且肮脏:-)

SELECT CAST(REPLACE(CAST(@x AS VARCHAR(MAX)),' rftID="',' rftID="q')  AS XML);

这里有一个干净的方法:

DECLARE @x  XML='<root>
  <TemplateQuestion>
    <Row rfqID="1" rftID="1" questionDesc="Question 1" responseType="1" rfqDisplayOrder="1" deletedBit="0" />
    <Row rfqID="2" rftID="1" questionDesc="Question 2" responseType="2" rfqDisplayOrder="2" deletedBit="0" />
    <Row rfqID="3" rftID="1" questionDesc="Question 3" responseType="3" rfqDisplayOrder="3" deletedBit="0" />
  </TemplateQuestion>
</root>';
SELECT
(
    SELECT 'q' + R.value('@rfqID','varchar(max)') AS [@rfqID]
          ,R.value('@rftID','int') AS [@rftID]
          ,R.value('@questionDesc','varchar(max)') AS [@questionDesc]
          --other attributes similar    
    FROM @x.nodes('/root/TemplateQuestion/Row') AS A(R)
    FOR XML PATH('Row'),ROOT('TemplateQuestion'),TYPE
)
FOR XML PATH('root');   

相关内容

  • 没有找到相关文章

最新更新