我的情况是这样的(简化):
DECLARE @period XML = (
SELECT
'2012' 'period'
FOR XML PATH(''), ROOT ('survey'))
DECLARE @persons XML = (
SELECT
Person.Name 'users/person'
FROM Person
FOR XML PATH(''), ROOT ('company'))
SET @persons.modify('insert sql:variable("@period") as first into (/company)[1]')
SELECT @persons
这给了我一个像这样的XML:
<company>
<survey>
<period>2012</period>
</survey>
<users>
<person>Dubach</person>
</users>
<users>
<person>Pletscher</person>
</users>
...
现在我需要像这样向根节点添加一个 XML 架构:
<company xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.mydomain.com/xmlns/bla/blabla/myschema.xsd" xmlns="http://www.mydomain.com/xmlns/bla/blabla">
<survey>
<period>2012</period>
</survey>
<users>
<person>Dubach</person>
</users>
<users>
<person>Pletscher</person>
</users>
...
Microsoft说我必须在 SELECT 语句之前使用 WITH XMLNAMESPACES,但这在我的情况下不起作用。
如何添加这些 xml命名空间?
将
声明与选择分开,然后按照说明使用with xmlnamespaces
。
DECLARE @persons XML
;with xmlnamespaces (
'http://www.mydomain.com/xmlns/bla/blabla' as ns,
'http://www.w3.org/2001/XMLSchema-instance' as xsi
)
select @persons = (
select
Person.Name as 'ns:users/person'
FROM Person
FOR XML PATH(''), ROOT ('company')
)
set @persons.modify('insert ( attribute xsi:schemaLocation {"http://www.mydomain.com/xmlns/bla/blabla/myschema.xsd"}) into (/company)[1]')
我找到了在此处添加所有命名空间的解决方案:
https://stackoverflow.com/a/536781/1306012
显然这不是很"好"的风格,但就我而言,它可以工作,我还没有找到另一个可行的解决方案。
溶液
DECLARE @period XML = (
SELECT
'2012' 'period'
FOR XML PATH(''), ROOT ('survey'))
DECLARE @persons XML = (
SELECT
Person.Name 'users/person'
FROM Person
FOR XML PATH(''), ROOT ('company'))
SET @persons.modify('insert sql:variable("@period") as first into (/company)[1]')
-- SOLUTION
SET @persons = replace(cast(@persons as varchar(max)), '<company>', '<company xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.mydomain.com/xmlns/bla/blabla/myschema.xsd" xmlns="">')
SELECT @persons