Json write无法序列化

Question

过程：

1. 创建Player类。

2. 创建播放器List<Player>()。

3. 将玩家添加到列表中。

4. 编写一个json串行文件。

   当我点击writeJson按钮时，我收到错误：

   "Type `'EditPlayers.Player'` cannot be serialized. Consider marking it with the 
   `DataContractAttribute` attribute, and marking all of its members you want serialized 
   with the `DataMemberAttribute` attribute.  If the type is a collection, consider marking 
   it with the `CollectionDataContractAttribute`.See the Microsoft .NET Framework 
   documentation for other supported types."
   

问题：

如何用CollectionDataContractAttribute标记List<Player>()。

class Player
{
public int MemberId { get; set; }
public int Gender { get; set; }
public string LName { get; set; }
public string FName { get; set; }
public int Tee { get; set; }
public int Team { get; set; }
public int Flight { get; set; }
public int Ohc { get; set; }
public decimal HcIx { get; set; }
}
private async void writeJason_Click(object sender, RoutedEventArgs e)
{
try
{
await writeJsonAsync();
}
catch
{
}
}
private async void readJason_Click(object sender, RoutedEventArgs e)
{
await deserializerJsonAsync();
}
private List<Player> buildObjectGraph()
{
var players = new List<Player>();
players.Add(new Player() {MemberId=1, Gender=0, LName="Player", FName="New", Tee=1, Team=0, Flight=0, Ohc=0, HcIx=0M});
players.Add(new Player() {MemberId=2, Gender=0, LName="Draw", FName="Blind", Tee=1, Team=0, Flight=0, Ohc=0, HcIx=0M});
players.Add(new Player() {MemberId=3, Gender=0, LName="Moles", FName="Mike", Tee=1, Team=4, Flight=1, Ohc=2, HcIx=2.0M});
players.Add(new Player() {MemberId=4, Gender=0, LName="Broemeling", FName="Donald", Tee=1, Team=4, Flight=2, Ohc=10, HcIx=10.0M});
players.Add(new Player() {MemberId=5, Gender=0, LName="Nelson", FName="David", Tee=1, Team=4, Flight=3, Ohc=11, HcIx=11.7M});
players.Add(new Player() {MemberId=6, Gender=0, LName="Moles", FName="David", Tee=1, Team=4, Flight=4, Ohc=20, HcIx=20.0M});
players.Add(new Player() {MemberId=7, Gender=0, LName="Player", FName="A", Tee=1, Team=1, Flight=1, Ohc=0, HcIx=0M});
players.Add(new Player() {MemberId=8, Gender=0, LName="Player", FName="B", Tee=1, Team=1, Flight=2, Ohc=0, HcIx=0M});
players.Add(new Player() {MemberId=9, Gender=0, LName="Player", FName="C", Tee=1, Team=1, Flight=3, Ohc=0, HcIx=0M});
players.Add(new Player() {MemberId=10,Gender=0, LName="Player", FName="D", Tee=1, Team=1, Flight=4, Ohc=0, HcIx=0M});
return players;
}
private async Task writeJsonAsync()
{
var allPlayers = buildObjectGraph();
var serializer = new DataContractJsonSerializer(typeof(List<Player>));
//using (var stream = await ApplicationData.Current.LocalFolder.OpenStreamForWriteAsync(
//    JSONFILENAME,
//    CreationCollisionOption.ReplaceExisting))
using (var stream = await ApplicationData.Current.LocalFolder.OpenStreamForWriteAsync(
JSONFILENAME, CreationCollisionOption.ReplaceExisting))
{
serializer.WriteObject(stream, allPlayers);
}
resultTextBlock.Text = "Write succeeded";
}

Answer 1

您不需要用CollectionDataContractAttribute标记List<Player>()。相反，您需要使Player类可由DataContractJsonSerializer序列化，如文档所述：数据协定序列化程序支持的类型。

最简单的解决方案是用Serializable属性标记Player：

[Serializable]
class Player
{
// Remainder unchanged
}

或者，您可以使用[DataContract]和[DataMember]属性对其进行注释：

[DataContract]
class Player
{
[DataMember]
public int MemberId { get; set; }
[DataMember]
public int Gender { get; set; }
[DataMember]
public string LName { get; set; }
[DataMember]
public string FName { get; set; }
[DataMember]
public int Tee { get; set; }
[DataMember]
public int Team { get; set; }
[DataMember]
public int Flight { get; set; }
[DataMember]
public int Ohc { get; set; }
[DataMember]
public decimal HcIx { get; set; }
}

无论哪种方式，您的List<Player>都可以通过DataContractJsonSerializer进行序列化。

请注意，数据协定序列化是选择加入的，因此必须使用[DataMember]标记要序列化的每个属性或字段。