我有一个javascript函数,当我在页面上只有一个元素时,它就可以工作,但是对于多个项目,我不知道如何将每个项目与其相应的图像配对。
在这个JSFiddle中,我目前拥有的内容被布置出来。当您将鼠标悬停在"链接 3"上时,它的行为正常,图像应该在鼠标下方停留在链接上时出现。但是当我将鼠标悬停在其他链接上时,他们不知道要显示哪个项目。
我可以将唯一的 slug 传递给链接中的任何项目。有谁知道正确连接每个项目的最佳方法?
https://jsfiddle.net/xw2Lvvj7/
var $img = $('.image');
$img.hide();
$('.hidden-overlay').mousemove(function(e) {
$img.stop(1, 1).fadeIn();
$('.image').offset({
top: e.pageY - ($img.outerHeight() / 2),
left: e.pageX - ($img.outerWidth() / 2)
});
}).mouseleave(function() {
$img.fadeOut();
});
body {
padding: 90px;
}
.link {
background: red;
position: relative;
z-index: 1;
}
.image {
background-size: cover;
height: 90px;
width: 90px;
position: absolute;
z-index: 2;
}
.hidden-overlay {
position: absolute;
top: 0px;
left: 0px;
width: 100%;
height: 100%;
z-index: 3
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<a class="link" data-slug="1">
link 1
<div class="image" style="background-image: url('http://via.placeholder.com/350x150');" data-slug="1"></div>
<div class="hidden-overlay" data-slug="1"></div>
</a>
<br>
<br>
<br>
<br>
<a class="link" data-slug="2">
link 2
<div class="image" style="background-image: url('http://via.placeholder.com/450x450');" data-slug="2"></div>
<div class="hidden-overlay" data-slug="2"></div>
</a>
<br>
<br>
<br>
<br>
<a class="link" data-slug="3">
link 3
<div class="image" style="background-image: url('http://via.placeholder.com/100x100');" data-slug="3"></div>
<div class="hidden-overlay" data-slug="3"></div>
</a>
</body>
你可以找到他们的每个.image
类父类
var $img = $('.image');
$img.hide();
$('.hidden-overlay').mousemove(function(e) {
// Find the [.image] classes inside the [.link] parent classes for every .hidden-overlay
var oImageHover = $(this).parents('.link').find('.image');
oImageHover.stop(1, 1).fadeIn();
oImageHover.offset({
top: e.pageY - (oImageHover.outerHeight() / 2),
left: e.pageX - (oImageHover.outerWidth() / 2)
});
}).mouseleave(function() {
// The same thing as well when the element was out of focus
var oImageLeave = $(this).parents('.link').find('.image');
oImageLeave.fadeOut();
});
body {
padding: 90px;
}
.link {
background: red;
position: relative;
z-index: 1;
}
.image {
background-size: cover;
height: 90px;
width: 90px;
position: absolute;
z-index: 2;
}
.hidden-overlay {
position: absolute;
top: 0px;
left: 0px;
width: 100%;
height: 100%;
z-index: 3
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<a class="link" data-slug="1">
link 1
<div class="image" style="background-image: url('http://via.placeholder.com/350x150');" data-slug="1"></div>
<div class="hidden-overlay" data-slug="1"></div>
</a>
<br>
<br>
<br>
<br>
<a class="link" data-slug="2">
link 2
<div class="image" style="background-image: url('http://via.placeholder.com/450x450');" data-slug="2"></div>
<div class="hidden-overlay" data-slug="2"></div>
</a>
<br>
<br>
<br>
<br>
<a class="link" data-slug="3">
link 3
<div class="image" style="background-image: url('http://via.placeholder.com/100x100');" data-slug="3"></div>
<div class="hidden-overlay" data-slug="3"></div>
</a>
<body>
希望这对您的情况有所帮助