>我正在尝试预替换以获取动态网址,
代码是:
<span>
<img src="/List/Detail/c0954c57-57ca-4f32-841d-de2b61a5087c/5358455" />
</span>
我需要提取:只有/List/Detail/c0954c57-57ca-4f32-841d-de2b61a5087c/5358455
我试过:/Listing/AdDetail/
试试这个:
preg_match("/<img src="(.*)"/", $input_line, $output_array);
使用此正则表达式获取">您的链接"之间的链接
(?<=")(.*)(?=")
注意:它适用于PHP,但不适用于Javascript。Lookback在Javascript中不受支持!
注2:此答案仅针对您的简短信息指定。我建议您更新您的问题,提供更多细节,以获得更好的代码示例!
public static Set<String> getImgStr(String htmlStr) {
Set<String> pics = new HashSet<>();
String img = "";
Pattern p_image;
Matcher m_image;
String regEx_img = "<img.*src\s*=\s*(.*?)[^>]*?>";
p_image = Pattern.compile
(regEx_img, Pattern.CASE_INSENSITIVE);
m_image = p_image.matcher(htmlStr);
while (m_image.find()) {
img = m_image.group();
Matcher m = Pattern.compile("src\s*=\s*"?(.*?)("|>|\s+)").matcher(img);
while (m.find()) {
pics.add(m.group(1));
}
}
return pics;
}