用于多个接口的装饰器 - AutoFac中的圆形依赖谜语



我来自ninject,但我决定尝试一下AutoFac,因为它似乎更积极地开发。到目前为止,我可以说注册装饰器并不像使用.WhenInjectedExactlyInto语法那样简单。无论如何,请忍受我,因为我是AutoFac Newbie。

这是问题:

i具有由A_Decorator装饰的接口IA的类型AA_Decorator实现了接口IAIB,反过来应由AB_Decorator装饰,该CC_8也将同时实现IAIBAB_Decorator采用IAIB类型的两种依赖项(因此,这是两者的装饰器),但它们都应分辨到A_Decorator的同一实例。看起来像这样:AB_Decorator(A_Decorator(A) as IA, A_Decorator(A) as IB)。当请求类型IA或从AUTOFAC容器中键入IB的服务时,他们应引用一个AB_Decorator实例。

用Word描述有点棘手,但是这是我可以提出的最简单的代码示例(我已经在构造函数中添加了实例ID和跟踪消息以查看正在发生的事情):

using System;
using Autofac;
namespace AutofacExample
{
    internal interface IA { }
    internal interface IB { }
    class A : IA
    {
        static int _instanceCounter;
        readonly int Id = ++_instanceCounter;
        public A()
        {
            Console.WriteLine(this);
        }
        public override string ToString()
        {
            return $"{GetType().Name}[{nameof(Id)}={Id}]";
        }
    }
    class A_Decorator : IA, IB
    {
        static int _instanceCounter = 10;
        readonly int Id = ++_instanceCounter;
        /* decorated1 should reference instance of A */
        public A_Decorator(IA decoratedA)
        {
            Console.WriteLine($"{this}({nameof(decoratedA)}={decoratedA})");
        }
        public override string ToString()
        {
            return $"{GetType().Name}[{nameof(Id)}={Id}]";
        }
    }
    class AB_Decorator : IA, IB
    {
        static int _instanceCounter = 100;
        readonly int Id = ++_instanceCounter;
        /* Both decorated1 and decorated2 should reference the same instance of A_Decorator */
        public AB_Decorator(IA decoratedA, IB decoratedB)
        {
            Console.WriteLine($"{this}({nameof(decoratedA)}={decoratedA}, {nameof(decoratedB)}={decoratedB})");
        }
        public override string ToString()
        {
            return $"{GetType().Name}[{nameof(Id)}={Id}]";
        }
    }
    class Program
    {
        static void Main(string[] args)
        {
            ContainerBuilder builder = new ContainerBuilder();
            builder
                .RegisterType<A>()
                .Named<IA>(nameof(A))
                .SingleInstance();
            builder
                .RegisterType<A_Decorator>()
                .Named<IA>(nameof(A_Decorator))
                .Named<IB>(nameof(A_Decorator))
                .SingleInstance();
            builder
                .RegisterType<AB_Decorator>()
                .Named<IA>(nameof(AB_Decorator))
                .Named<IB>(nameof(AB_Decorator))
                .SingleInstance();
            /* A is decorated by A_Decorator as IA */
            builder
                .RegisterDecorator<IA>(
                    (c, decorated) =>
                        c.ResolveNamed<IA>(nameof(A_Decorator), TypedParameter.From(decorated)),
                    nameof(A))
                //.Keyed<IA>("innerA")
                //.Keyed<IB>("innerB")
                .SingleInstance();
            /* Trying to register AB_Decorator as IA creates circular dependency */
            //builder
            //    .RegisterDecorator<IA>(
            //        (c, decorated) =>
            //            c.ResolveNamed<IA>(nameof(AB_Decorator), TypedParameter.From(decorated)),
            //        "innerA")
            //    .SingleInstance();
            /* A_Decorator is decorated by AB_Decorator as IB */
            builder
                .RegisterDecorator<IB>(
                        (c, decorated) =>
                            c.ResolveNamed<IB>(nameof(AB_Decorator), TypedParameter.From(decorated)),
                        nameof(A_Decorator) /* "innerB" */)
                    .SingleInstance();
            IContainer container = builder.Build();
            IA a = container.Resolve<IA>();
            IB b = container.Resolve<IB>();
            Console.WriteLine($"{nameof(a)} == {nameof(b)} ? {ReferenceEquals(a, b)}");
            Console.WriteLine($"{nameof(a)} is {a.GetType().Name}");
            Console.WriteLine($"{nameof(b)} is {b.GetType().Name}");
        }
    }
}

不幸的是,请求IA的实例给我A_Decorator,而对于IB,我获得了AB_Decorator。试图删除额外的装饰器注册块会导致循环依赖性异常(DependencyResolutionException: Circular component dependency detected: System.Object -> AutofacExample.AB_Decorator -> System.Object -> AutofacExample.AB_Decorator),我无法使其工作尝试各种命名注册的组合。

有人知道解决方案吗?预先感谢。

问题

问题在于AB_Decorator的装饰器注册。特别是lambda函数解决AB_Decorator

( c, decorated ) => c.ResolveNamed<IA>( nameof( AB_Decorator ), TypedParameter.From( decorated ) );

AB_Decorator的构造函数进行了2个参数,这两个参数都应该是A_Decorator的同一实例,该实例与decorated相同。但是,decorated仅通过TypedParameter.From( decorated )作为参数传递。因此,AUTOFAC将尝试通过容器解决第二个参数。

现在,IB的注册表明,我们应该获得一个包裹在AB_Decorator中的A_Decorator的单例实例。因此,要解决IB,容器必须构造AB_Decorator。有问题,我们目前正在尝试将AB_Decorator解析为IA,但是我们需要IB来满足用于IA构建的AB_Decorator的构造函数参数。和IB在容器中注册为AB_Decorator。所以你得到:

AB_Decorator(A_Decorator(A) as IA, AB_Decorator(A_Decorator(A) as IA, AB_Decorator(etc...))

解决方案

解决AB_Decorator时,我们需要将decorated传递到两个参数中。这样:

builder
    .RegisterDecorator<IA>(
        ( c, decorated ) =>
            c.ResolveNamed<IA>( nameof( AB_Decorator ),
                new TypedParameter( typeof( IA ), decorated ),
                new TypedParameter( typeof( IB ), decorated )
            )
        ,"innerA"
    )
    .SingleInstance();

builder
    .RegisterDecorator<IB>(
        ( c, decorated ) =>
            c.ResolveNamed<IB>( nameof( AB_Decorator ),
                new TypedParameter( typeof( IA ), decorated ),
                new TypedParameter( typeof( IB ), decorated )
            )
        , nameof( A_Decorator ) /* "innerB" */
    )
    .SingleInstance();

现在,我们向IAIB参数发送decorated。直接构建TypedParameter实例,我可以指定我希望该实例在参数列表中满足的类型,在这种情况下为AB_Decorator

您去这里:

ContainerBuilder builder = new ContainerBuilder();
builder
    .RegisterType<A>()
    .Named<IA>(nameof(A))
    .SingleInstance();
builder
    .RegisterType<A_Decorator>()
    .Named<IA>(nameof(A_Decorator))
    .Named<IB>(nameof(A_Decorator))
    .WithParameter(new ResolvedParameter((pi, c) => pi.Name == "decoratedA", 
        (pi, c) => c.ResolveNamed<IA>(nameof(A))))
    .SingleInstance();
builder
    .RegisterType<AB_Decorator>()
    .As<IA, IB>()
    .WithParameter(new ResolvedParameter((pi, c) => pi.Name == "decoratedA",
        (pi, c) => c.ResolveNamed<IA>(nameof(A_Decorator))))
    .WithParameter(new ResolvedParameter((pi, c) => pi.Name == "decoratedB",
        (pi, c) => c.ResolveNamed<IB>(nameof(A_Decorator))))
    .SingleInstance();
IContainer container = builder.Build();

打印:

A[Id=1]
A_Decorator[Id=11](decoratedA=A[Id=1])
AB_Decorator[Id=101](decoratedA=A_Decorator[Id=11], decoratedB=A_Decorator[Id=11])
a == b ? True
a is AB_Decorator
b is AB_Decorator

API令人困惑,因为在这种情况下您不需要RegisterDecorator()(它是为了一次装饰一组组件)。

(如果我们可以烘烤整体,那将是很好的:

    .WithParameter(new ResolvedParameter((pi, c) => pi.Name == "decoratedA", 
        (pi, c) => c.ResolveNamed<IA>(nameof(A))))

成语降至AUTOFAC中的更简单的WithParameter()过载;我认为,如果您在这里看到胜利,这将是一个很好的建议。)

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