如何通过Python插座运行多个命令

Question

我的代码有问题，我想通过插座在我的Virual机器上运行一个命令。我发现了多个任务，命令的问题。例如，如果我打开Excel，我的套接字服务器已经冻结，并且在我手动关闭Excel应用程序之前，我无法通过CMD运行另一个命令。

我应该更改代码以一次在我的虚拟机上打开多个应用程序？(例如。我想一次打开四个XLSX文件(

server.py

import socket
import subprocess
import os
from threading import Thread

def check_ping(hostname):
    response = os.system("ping " + hostname)
    # and then check the response...
    if response == 0:
        pingstatus = "Network Active"
    else:
        pingstatus = "Network Error"
    return(pingstatus)
def run_path(path):
    response = os.system(path)
    # and then check the response..
    return('ok')

def Main():
    host = "localhost"
    port = 5000
    mySocket = socket.socket()
    mySocket.bind((host,port))
    mySocket.listen(1)
    conn, addr = mySocket.accept()
    print ("Connection from: " + str(addr))
    while True:
            data = conn.recv(1024).decode()
            if not data:
                    break
            #print ("from connected  user: " + str(data))
            #data = str(data)
            #hostname = data.replace('ping ', '')
            print ("sending: " + str(data))
            #print(hostname)
            conn.send(data.encode())
            if 'ping' in str(data):
                hostname = data.replace('ping ', '')
                pingstatus = check_ping(hostname)
                print(pingstatus)
            elif 'open' in str(data):
                path = str(data).replace('open ', '')
                run_path(path)


    conn.close()
if __name__ == '__main__':
    Main()

client.py

import socket
def Main():
        host = '127.0.0.1'
        port = 5000
        mySocket = socket.socket()
        mySocket.connect((host,port))
        message = input(" -> ")
        while message != 'q':
                mySocket.send(message.encode())
                data = mySocket.recv(1024).decode()
                print ('Received from server: ' + data)
                message = input(" -> ")
        mySocket.close()
if __name__ == '__main__':
    Main()

Answer 1

te能够在上一个命令返回之前运行一个新命令，您只需要等待该事件即可。这意味着您应该使用子过程模块而不是system函数：

def run_path(path):
    response = subprocess.Process(path, shell=True)
    # and then continue without waiting...
    return('ok')

，但是如果您想将任何东西归还给同伴，那真的没有意义。此外，从远程客户端启动GUI程序而不能够控制它，也没有阻止它。

我怕你在这里追逐一个怪异的动物...