我们如何从参数和 kwarg 打印参数列表?

Question

>假设我们有一个可变参数函数，如下所示：

def foo(*args, **kwargs):
pass

我想编辑 foo，以便它打印参数列表。例如，我们需要以下代码...

foo(98, 99, 100, a = 1, b = 2, c = 3)

。要打印...

98, 99, 100, a = 1, b = 2, c = 3   

Answer 1

这将做你想要的：

def foo(*args, **kwargs):
print(args + tuple('{} = {}'.format(key,val) for key,val in kwargs.items()))

Answer 2

以下似乎可以解决问题：

import itertools
rep_kwarg = lambda kwarg: kwarg[0] + " = " + str(kwarg[1])
def foo(*args, **kwargs):
kwargs2 = map(rep_kwarg, kwargs.items())
it_combo = itertools.chain(args, kwargs2)
it_combo_str = map(str, it_combo)
arg_list = ', '.join(it_combo_str)
print("RESULT == ", repr(arg_list))

args = [98, 99, 100]
kwargs = {
"a": 1,
"b": 2,
"c": 3
}
foo(*args, **kwargs)
foo(98, 99, 100, a = 1, b = 2, c = 3)

控制台输出为：

RESULT ==  '98, 99, 100, a = 1, b = 2, c = 3'
RESULT ==  '98, 99, 100, a = 1, b = 2, c = 3'