DB Fiddle
CREATE TABLE sales (
id int auto_increment primary key,
country VARCHAR(255),
sales_date DATE,
sales_volume INT,
fix_costs INT
);
INSERT INTO sales
(country, sales_date, sales_volume, fix_costs
)
VALUES
("DE", "2020-01-03", "500", "0"),
("NL", "2020-01-03", "320", "0"),
("FR", "2020-01-03", "350", "0"),
("None", "2020-01-30", "0", "2000"),
("DE", "2020-02-15", "700", "0"),
("NL", "2020-02-15", "420", "0"),
("FR", "2020-02-15", "180", "0"),
("None", "2020-02-29", "0", "5000"),
("DE", "2020-03-27", "180", "0"),
("NL", "2020-03-27", "670", "0"),
("FR", "2020-03-27", "970", "0"),
("None", "2020-03-31", "0", "4000");
预期结果:
sales_date country sales_volume fix_costs
2020-01-03 DE 500 27.6 (=2000/31 = 64.5 * 0.42)
2020-01-03 FR 350 19.3 (=2000/31 = 64.5 * 0.30)
2020-01-03 NL 320 17.6 (=2000/31 = 64.5 * 0.28)
2020-02-15 DE 700 92.8 (=5000/29 = 172.4 * 0.54)
2020-02-15 FR 180 23.9 (=5000/29 = 172.4 * 0.14)
2020-02-15 NL 420 55.7 (=5000/29 = 172.4 * 0.32)
2020-03-27 DE 180 12.8 (=4000/31 = 129.0 * 0.10)
2020-03-27 FR 970 68.8 (=4000/31 = 129.0 * 0.53)
2020-03-27 NL 670 47.5 (=4000/31 = 129.0 * 0.37)
在上表中,我每月有fix_costs
现在,我想将每月的fix_costs
划分为该月的每天和每个国家。
因此,我使用以下公式计算每个月的fix_cost_per_day
:SUM(fix_costs) / DAY(LAST_DAY(sales_date)) AS fix_cost_per_day
然而,我不知道如何将daily revenue_share per country
应用于fix_cost_per_day
我需要什么来修改我的查询以获得预期结果:
SELECT
sales_date,
country,
SUM(sales_volume),
SUM(fix_costs) / DAY(LAST_DAY(sales_date)) AS fix_cost_per_day
FROM sales
GROUP BY 1,2;
首先:您的currenet查询不能满足您的要求。看起来你实际上需要fix_costs
上的每月窗口金额。所以我会从开始
select
sales_date,
country,
sum(sales_volume),
sum(sum(fix_costs)) over(partition by year(sales_date), month(sales_date))
/ day(last_day(sales_date))
as fix_cost_per_day
from sales
group by 1,2;
这产生:
sales_date|country|sum(sales_volume(|fix_cost_per_day:---------------------------------------|:---------------------------------------|----------------:|----------------2020-01-03 |日期|500 |64.51612020-01-03 | FR | 350 | 64.51612020-01-03 | NL | 320 | 64.51612020-01-30|无|0|64.51612020-02-15 |日期|700 | 172.41382020-02-15 | FR|180 | 172.41382020-02-15 | NL | 420 | 172.41382020-02-29|无|0|172.41382020-03-27 |日期|180 | 129.03232020-03-27 | FR | 970 | 129.03232020-03-27 | NL | 670 | 129.03232020-03-31|None|0|129.0323
从那时起,您可以添加考虑";每个国家的每日收入份额";。据我所知,你的问题是:
select
sales_date,
country,
sum(sales_volume),
sum(sum(fix_costs)) over(partition by year(sales_date), month(sales_date))
/ day(last_day(sales_date))
* sum(sales_volume)
/ sum(sum(sales_volume)) over(partition by sales_date)
as fix_cost_per_day
from sales
group by 1,2;
退货:
sales_date|country|sum(sales_volume(|fix_cost_per_day:---------------------------------------|:---------------------------------------|----------------:|----------------2020-01-03|DE |500 |27.570995312020-01-03 | FR | 350 | 19.299696722020-01-03 | NL | 320 | 17.645437002020-01-30|None|0|null2020-02-15|DE|700|92.838196292020-02-15 | FR|180 | 23.872679052020-02-15 | NL | 420 | 55.702917772020-02-29|None|0|null22020-03-27|DE|180|12.761432122020-03-27 | FR | 970 | 68.769939742020-03-27 | NL | 670 | 47.500886212020-03-31|None|0|null
在DB Fiddle上演示
如果需要,可以通过将查询转为子查询并在外部查询中进行筛选来删除国家/地区'None'
的记录。
要分配数据,可以使用窗口函数。你需要按月对各种值求和,然后求和除以:
SELECT sales_date, country,
SUM(sales_volume),
SUM(fix_costs) / DAY(LAST_DAY(sales_date)) AS fix_cost_per_day,
(SUM(SUM(fix_costs)) OVER (PARTITION BY yyyy, mm) / DAY(LAST_DAY(sales_date))) *
(SUM(sales_volume) / SUM(SUM(sales_volume)) OVER (PARTITION BY yyyy, mm)) as allocated
FROM (SELECT s.*, YEAR(sales_date) as yyyy, MONTH(sales_date) as mm
FROM sales s
) s
GROUP BY 1,2;
这里有一个db<gt;不停摆弄
请注意,子查询并不是严格需要的。这对每个月处理分区很有帮助。