rn-fetch-blob 错误:RNFetchBlob.fetchBlobForm 无法创建请求正文

Question

async postFileUpload(payload) {
const rnfetchfile = RNFetchBlob.wrap(payload.uri);
try {
console.log(
'POST',
'https://******.***.**/******/***/upload_*******_file',
{
...this.config,
'Content-Type': 'multipart/form-data',
},
[
// element with property `filename` will be transformed into `file` in form data
{
name: 'files',
filename: payload.name,
data: rnfetchfile.replace('file://file:///', 'file://'),
},
],
);
const res = await RNFetchBlob.fetch(
'POST',
'https://******.***.**/******/***/upload_*******_file',
{
...this.config,
'Content-Type': 'multipart/form-data',
},
[
// element with property `filename` will be transformed into `file` in form data
{
name: 'files',
filename: payload.name,
data: rnfetchfile.replace('file://file:///', 'file://'),
},
],
);
const response = JSON.parse(res.data);
console.log('api upload adpostimage', response);
return response;
} catch (err) {
console.log('postFileUpload', err.response, err);
Toast.show(err.response.data.message, Toast.SHORT);
throw err.response.data;
}

res 抛出错误 在控制台消息是

POST https://******.***.**/******/***/upload_*******_file {Content-Type: "multipart/form-data", Authorization: "Bearer ******.***.*****"} 
[{…}]
0:
name: "files"
filename: "*****.pdf"
data: "RNFetchBlob-file://Users/********/tmp/*****/B****.pdf"}

postFileUpload undefined Error: RNFetchBlob.fetchBlobForm failed to create request body
at index.js:313
at MessageQueue.__invokeCallback (MessageQueue.js:483)
at MessageQueue.js:135
at MessageQueue.__guard (MessageQueue.js:384)
at MessageQueue.invokeCallbackAndReturnFlushedQueue (MessageQueue.js:134)
at debuggerWorker.js:69

我正在尝试使用 rn-fetch-blob 上传文件，发生了一些疯狂的事情 rnfetchfile.replace('file：//file：///'， 'file://'(，因为 file://file///输出似乎不正确 我认为这主要是ios问题，请帮帮我

Answer 1

正如这里所说的，只需使用decodeURIComponent(uri)

这是我的代码：

const realPath = Platform.OS === 'ios' ? uri.replace('file://', '') : uri;
const data = [
{
name: 'file',
filename,
type,
data: RNFetchBlob.wrap(decodeURIComponent(realPath)),
},
{name: 'bla', data: 'bla'}
]

Answer 2

尝试将 file://file://替换为空字符串。

rnfetchfile.replace('file://file:///', '') 

– @Abhishek Ghosh 评论是一个需要技巧，它将起作用，但该文件在 uri 中不可用.. 您上传的文件无法打开

我试过做

data: decodeURIComponent(rnfetchfile.replace('file://file:///', 'file:///')

它奏效了，希望这有帮助