在 JFel 残留大小上调整立方曲线的大小

Question

我有这个曲线形状，我希望相对于我的 JFrame 的大小相应地调整宽度和高度的大小，例如我的 JFrame 大小是 setSize(440， 300(; -- 然后如果我最大化我的 JFrame，我希望曲线形状也调整大小，以便形状保持其实际图形。任何帮助，提前感谢。谢谢

这是我的代码：

float offset = (float) Math.sin(Math.PI);
x1 = offset;
y1 = (height/4.0f) - 4.0f;
x1ctl = ((width/4) - 140) + 90.0f;
y1ctl = ((height/4) - 100) + 20.0f;
x2ctl = ((width/4) - 10.0f) + 60.0f;
y2ctl = ((height/4) - 8.0f) + 1.0f;
x2 = (width/2.0f) - 20.0f;
y2 = offset - 4.0f;
curve = new CubicCurve2D.Float(
        x1,y1,
        x1ctl,y1ctl,
        x2ctl,y2ctl,
        x2,y2);
g2d.draw(curve);

Answer 1

您可以覆盖paintComponent并使用组件的尺寸。下面是一个基于问题中参数的示例：

import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.geom.CubicCurve2D;
import javax.swing.JComponent;
import javax.swing.JFrame;
import javax.swing.SwingUtilities;
public class CubicCurveComponentTest extends JComponent {
    public void paintComponent(Graphics g) {
        float offset = (float) Math.sin(Math.PI);
        float x1 = offset;
        float y1 = (getHeight()/4.0f) - 4.0f;
        float x1ctl = ((getWidth()/4) - 140) + 90.0f;
        float y1ctl = ((getHeight()/4) - 100) + 20.0f;
        float x2ctl = ((getWidth()/4) - 10.0f) + 60.0f;
        float y2ctl = ((getHeight()/4) - 8.0f) + 1.0f;
        float x2 = (getWidth()/2.0f) - 20.0f;
        float y2 = offset - 4.0f;
        CubicCurve2D curve = new CubicCurve2D.Float(
                x1,y1,
                x1ctl,y1ctl,
                x2ctl,y2ctl,
                x2,y2);
        Graphics2D g2 = (Graphics2D) g;
        g2.draw(curve);
    }
    private static void createAndShowGUI() {    
        JFrame f = new JFrame("Cubic Curve Test");
        f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        f.setSize(440, 300);
        f.add(new CubicCurveComponentTest());
        f.setVisible(true);
    }
    public static void main(String args[]) {
        Runnable doCreateAndShowGUI = new Runnable() {
            public void run() {
                createAndShowGUI();
            }
        };
        SwingUtilities.invokeLater(doCreateAndShowGUI);
    }
}

编辑：坐标示例

下面是从容器的给定初始尺寸 (440， 300( 和原始计算中使用的幻数派生的坐标示例：

    float x1 = 0;
    float y1 = getHeight() * 0.24f;
    float x1ctl =  getWidth() * 0.125f;
    float y1ctl = 0;
    float x2ctl = getWidth() * 0.24f;
    float y2ctl = getHeight() * 0.22f;
    float x2 = getWidth() * 0.45f;
    float y2 = -getHeight() * 0.013f;