带有确保的游戏框架中的单元测试控制器



我正在尝试发明某种模拟的固定动作发生器,或者确保自我自我自我来单位测试控制器方法。我发现了一些方法,例如使用固定注释确保使用确保的单位测试方法,并使用依赖注入测试Play2应用程序,但事实是,在此问题中,作者实际上不做单位测试,而是进行集成测试。

我的单位测试看起来像:

  trait MockDaoProvider extends IDaoProvider {
    def entityDao = entityDaoMock
  }
  val controller = new MyController with MockDaoProvider
  "MyController.list" should {
    "return an OK" in {
      entityDaoMock.list().returns(List())
      val result = controller.list()(FakeRequest())
      status(result) must equalTo(OK)
    }
  }

正如人们所看到的,我嘲笑依赖关系以隔离和测试控制器方法实际上所做的行为。

一切都可以,直到我使用cocurecial for myController.list方法使用安全性。现在我得到了一个例外,测试失败了。我不知道如何嘲笑,存根或超越安全性和userawareaction对象。我仍然不想将测试转换为路线(...)测试。他们旨在仅测试控制器的行为。

有人遇到同样的问题吗?可能有任何提示如何解决?

ps:游戏框架2.2.1,固定 - 2.1.2

似乎确实没有强调可测试性,这迫使用户提出了自己的新颖解决方案。用户jeantil这可能会有所帮助:

class FakeAuthenticatorStore(app:Application) extends AuthenticatorStore(app) {
  var authenticator:Option[Authenticator] = None
  def save(authenticator: Authenticator): Either[Error, Unit] = {
    this.authenticator=Some(authenticator)
    Right()
  }
  def find(id: String): Either[Error, Option[Authenticator]] = {
    Some(authenticator.filter(_.id == id)).toRight(new Error("no such authenticator"))
  }
  def delete(id: String): Either[Error, Unit] = {
    this.authenticator=None
    Right()
  }
}
abstract class WithLoggedUser(val user:User,override val app: FakeApplication = FakeApplication()) extends WithApplication(app) with Mockito{
  lazy val mockUserService=mock[UserService]
  val identity=IdentityUser(Defaults.googleId, user)
  import helpers._
  import TestUsers._
  def cookie=Authenticator.create(identity) match {
    case Right(authenticator) => authenticator.toCookie
  }
  override def around[T: AsResult](t: =>T): execute.Result = super.around {
    mockUserService.find(Defaults.googleId) returns Some(identity)
    UserService.setService(mockUserService)
    t
  }
}
  val excludedPlugins=List(
    ,"service.login.MongoUserService"
    ,"securesocial.core.DefaultAuthenticatorStore"
  )
  val includedPlugins = List(
    "helpers.FakeAuthenticatorStore"
  )
  def minimalApp = FakeApplication(withGlobal =minimalGlobal, withoutPlugins=excludedPlugins,additionalPlugins = includedPlugins)

然后允许这样的测试

"create a new user password " in new WithLoggedUser(socialUser,minimalApp) {
  val controller = new TestController
  val req: Request[AnyContent] = FakeRequest().
    withHeaders((HeaderNames.CONTENT_TYPE, "application/x-www-form-urlencoded")).
    withCookies(cookie) // Fake cookie from the WithloggedUser trait
  val requestBody = Enumerator("password=foobarkix".getBytes) andThen Enumerator.eof
  val result = requestBody |>>> controller.create.apply(req)
  val actual: Int= status(result)
  actual must be equalTo 201
}

在思考,探测和实验之后,我最终得到了一个优雅的解决方案。该解决方案依赖于依赖注入的"蛋糕模式"。这样:

控制器中的代码:

trait AbstractSecurity {
  def Secured(action: SecuredRequest[AnyContent] => Result): Action[AnyContent]
}
trait SecureSocialSecurity extends AbstractSecurity with securesocial.core.SecureSocial {
   def Secured(action: SecuredRequest[AnyContent] => Result): Action[AnyContent] = SecuredAction { action }
}
abstract class MyController extends Controller with AbstractSecurity {
  def entityDao: IEntityDao
  def list = Secured { request =>
    Ok(
      JsArray(entityDao.list())
    )
  }
}
object MyController extends MyController with PsqlDaoProvider with SecureSocialSecurity

和测试代码:

 trait MockedSecurity extends AbstractSecurity {
    val user = Account(NotAssigned, IdentityId("test", "userpass"), "Test", "User",
      "Test user", Some("test@user.com"), AuthenticationMethod("userPassword"))
    def Secured(action: SecuredRequest[AnyContent] => play.api.mvc.Result): Action[AnyContent] = Action { request =>
      action(new SecuredRequest(user, request))
    }
  }

  val controller = new MyController with MockDaoProvider with MockedSecurity
  "IssueController.list" should {
    "return an OK" in {
      entityDaoMock.list().returns(List())
      val result = controller.list()(FakeRequest())
      status(result) must equalTo(OK)
    }
  }

仍然存在一个缺点 - 测试也取决于固定类……但是...这真的是一个缺点吗?我不知道这种方法如何在更复杂的情况下起作用,我们会看到。